Solve the Inequality for x x/2+y/3>1

$\frac{x}{2} + \frac{y}{3} > 1$

Step 1

Subtract $\frac{y}{3}$ from both sides of the inequality.

$\frac{x}{2} > 1 - \frac{y}{3}$

Step 2

Multiply both sides by $2$ .

$\frac{x}{2} \cdot 2 > (1 - \frac{y}{3}) \cdot 2$

Step 3

Simplify.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{x}{2} \cdot 2 > (1 - \frac{y}{3}) \cdot 2$

Rewrite the expression.

$x > (1 - \frac{y}{3}) \cdot 2$

Simplify the right side.

Simplify $(1 - \frac{y}{3}) \cdot 2$ .

Apply the distributive property.

$x > 1 \cdot 2 - \frac{y}{3} \cdot 2$

Multiply $2$ by $1$ .

$x > 2 - \frac{y}{3} \cdot 2$

Multiply $- \frac{y}{3} \cdot 2$ .

Multiply $2$ by $- 1$ .

$x > 2 - 2 \frac{y}{3}$

Combine $- 2$ and $\frac{y}{3}$ .

$x > 2 + \frac{- 2 y}{3}$

Move the negative in front of the fraction.

$x > 2 - \frac{2 y}{3}$

Reorder $2$ and $- \frac{2 y}{3}$ .

$x > - \frac{2 y}{3} + 2$