Solve the Inequality for x -x/3>=5

$- \frac{x}{3} \geq 5$

Divide each term in $- \frac{x}{3} \geq 5$ by $- 1$ and simplify.

Divide each term in $- \frac{x}{3} \geq 5$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- \frac{x}{3}}{- 1} \leq \frac{5}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{\frac{x}{3}}{1} \leq \frac{5}{- 1}$

Divide $\frac{x}{3}$ by $1$ .

$\frac{x}{3} \leq \frac{5}{- 1}$

Simplify the right side.

Divide $5$ by $- 1$ .

$\frac{x}{3} \leq - 5$

Multiply both sides by $3$ .

$\frac{x}{3} \cdot 3 \leq - 5 \cdot 3$

Simplify.

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{x}{3} \cdot 3 \leq - 5 \cdot 3$

Rewrite the expression.

$x \leq - 5 \cdot 3$

Simplify the right side.

Multiply $- 5$ by $3$ .

$x \leq - 15$

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 15$

Interval Notation:

$(- \infty, - 15]$

Solve the Inequality for x -x/3>=5

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