Solve the Inequality for x x+(x+1)+(x+2)>60

$x + (x + 1) + (x + 2) > 60$

Step 1

Simplify $x + x + 1 + x + 2$ .

Add $x$ and $x$ .

$2 x + 1 + x + 2 > 60$

Add $2 x$ and $x$ .

$3 x + 1 + 2 > 60$

Add $1$ and $2$ .

$3 x + 3 > 60$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$3 x > 60 - 3$

Subtract $3$ from $60$ .

$3 x > 57$

Step 3

Divide each term in $3 x > 57$ by $3$ and simplify.

Divide each term in $3 x > 57$ by $3$ .

$\frac{3 x}{3} > \frac{57}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} > \frac{57}{3}$

Divide $x$ by $1$ .

$x > \frac{57}{3}$

Simplify the right side.

Divide $57$ by $3$ .

$x > 19$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x > 19$

Interval Notation:

$(19, \infty)$