Solve the Inequality for y 2(y+6)<=3y

$2 (y + 6) \leq 3 y$

Step 1

Simplify $2 (y + 6)$ .

Start simplifying.

$0 + 0 + 2 (y + 6) \leq 3 y$

Simplify by adding zeros.

$2 (y + 6) \leq 3 y$

Apply the distributive property.

$2 y + 2 \cdot 6 \leq 3 y$

Multiply $2$ by $6$ .

$2 y + 12 \leq 3 y$

Step 2

Move all terms containing $y$ to the left side of the inequality.

Subtract $3 y$ from both sides of the inequality.

$2 y + 12 - 3 y \leq 0$

Subtract $3 y$ from $2 y$ .

$- y + 12 \leq 0$

Step 3

Subtract $12$ from both sides of the inequality.

$- y \leq - 12$

Step 4

Divide each term in $- y \leq - 12$ by $- 1$ and simplify.

Divide each term in $- y \leq - 12$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- y}{- 1} \geq \frac{- 12}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} \geq \frac{- 12}{- 1}$

Divide $y$ by $1$ .

$y \geq \frac{- 12}{- 1}$

Simplify the right side.

Divide $- 12$ by $- 1$ .

$y \geq 12$

Step 5

The result can be shown in multiple forms.

Inequality Form:

$y \geq 12$

Interval Notation:

$[12, \infty)$

Solve the Inequality for y 2(y+6)<=3y

Related Questions

Support LCMGCF.com by disabling your adblocker.