Solve the Inequality for y -2x+3y>=3

$- 2 x + 3 y \geq 3$

Step 1

Add $2 x$ to both sides of the inequality.

$3 y \geq 3 + 2 x$

Step 2

Divide each term in $3 y \geq 3 + 2 x$ by $3$ and simplify.

Divide each term in $3 y \geq 3 + 2 x$ by $3$ .

$\frac{3 y}{3} \geq \frac{3}{3} + \frac{2 x}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} \geq \frac{3}{3} + \frac{2 x}{3}$

Divide $y$ by $1$ .

$y \geq \frac{3}{3} + \frac{2 x}{3}$

Simplify the right side.

Divide $3$ by $3$ .

$y \geq 1 + \frac{2 x}{3}$