Solve the Inequality for y -3(3y-2)<1-9y

$- 3 (3 y - 2) < 1 - 9 y$

Simplify $- 3 (3 y - 2)$ .

Rewrite.

$0 + 0 - 3 (3 y - 2) < 1 - 9 y$

Simplify by adding zeros.

$- 3 (3 y - 2) < 1 - 9 y$

Apply the distributive property.

$- 3 (3 y) - 3 \cdot - 2 < 1 - 9 y$

Multiply.

Multiply $3$ by $- 3$ .

$- 9 y - 3 \cdot - 2 < 1 - 9 y$

Multiply $- 3$ by $- 2$ .

$- 9 y + 6 < 1 - 9 y$

Move all terms containing $y$ to the left side of the inequality.

Add $9 y$ to both sides of the inequality.

$- 9 y + 6 + 9 y < 1$

Combine the opposite terms in $- 9 y + 6 + 9 y$ .

Add $- 9 y$ and $9 y$ .

$0 + 6 < 1$

Add $0$ and $6$ .

$6 < 1$

Since $6 > 1$ , there are no solutions.

No solution