Solve the Inequality for y -3y+12>=6

$- 3 y + 12 \geq 6$

Move all terms not containing $y$ to the right side of the inequality.

Subtract $12$ from both sides of the inequality.

$- 3 y \geq 6 - 12$

Subtract $12$ from $6$ .

$- 3 y \geq - 6$

Divide each term in $- 3 y \geq - 6$ by $- 3$ and simplify.

Divide each term in $- 3 y \geq - 6$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 y}{- 3} \leq \frac{- 6}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 y}{- 3} \leq \frac{- 6}{- 3}$

Divide $y$ by $1$ .

$y \leq \frac{- 6}{- 3}$

Simplify the right side.

Divide $- 6$ by $- 3$ .

$y \leq 2$

The result can be shown in multiple forms.

Inequality Form:

$y \leq 2$

Interval Notation:

$(- \infty, 2]$

Solve the Inequality for y -3y+12>=6

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