Solve the Inequality for y 7x+8y<=14x-16

$7 x + 8 y \leq 14 x - 16$

Step 1

Move all terms not containing $y$ to the right side of the inequality.

Subtract $7 x$ from both sides of the inequality.

$8 y \leq 14 x - 16 - 7 x$

Subtract $7 x$ from $14 x$ .

$8 y \leq 7 x - 16$

Step 2

Divide each term in $8 y \leq 7 x - 16$ by $8$ and simplify.

Divide each term in $8 y \leq 7 x - 16$ by $8$ .

$\frac{8 y}{8} \leq \frac{7 x}{8} + \frac{- 16}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 y}{8} \leq \frac{7 x}{8} + \frac{- 16}{8}$

Divide $y$ by $1$ .

$y \leq \frac{7 x}{8} + \frac{- 16}{8}$

Simplify the right side.

Divide $- 16$ by $8$ .

$y \leq \frac{7 x}{8} - 2$