Solve the Inequality for y x+3y>9

$x + 3 y > 9$

Subtract $x$ from both sides of the inequality.

$3 y > 9 - x$

Divide each term in $3 y > 9 - x$ by $3$ and simplify.

Divide each term in $3 y > 9 - x$ by $3$ .

$\frac{3 y}{3} > \frac{9}{3} + \frac{- x}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} > \frac{9}{3} + \frac{- x}{3}$

Divide $y$ by $1$ .

$y > \frac{9}{3} + \frac{- x}{3}$

Simplify the right side.

Simplify each term.

Divide $9$ by $3$ .

$y > 3 + \frac{- x}{3}$

Move the negative in front of the fraction.

$y > 3 - \frac{x}{3}$