Solve the Inequality for z z/-2-6<=-2

$\frac{z}{- 2} - 6 \leq - 2$

Move the negative in front of the fraction.

$- \frac{z}{2} - 6 \leq - 2$

Move all terms not containing $z$ to the right side of the inequality.

Add $6$ to both sides of the inequality.

$- \frac{z}{2} \leq - 2 + 6$

Add $- 2$ and $6$ .

$- \frac{z}{2} \leq 4$

Divide each term in $- \frac{z}{2} \leq 4$ by $- 1$ and simplify.

Divide each term in $- \frac{z}{2} \leq 4$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- \frac{z}{2}}{- 1} \geq \frac{4}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{\frac{z}{2}}{1} \geq \frac{4}{- 1}$

Divide $\frac{z}{2}$ by $1$ .

$\frac{z}{2} \geq \frac{4}{- 1}$

Simplify the right side.

Divide $4$ by $- 1$ .

$\frac{z}{2} \geq - 4$

Multiply both sides by $2$ .

$\frac{z}{2} \cdot 2 \geq - 4 \cdot 2$

Simplify.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{z}{2} \cdot 2 \geq - 4 \cdot 2$

Rewrite the expression.

$z \geq - 4 \cdot 2$

Simplify the right side.

Multiply $- 4$ by $2$ .

$z \geq - 8$

The result can be shown in multiple forms.

Inequality Form:

$z \geq - 8$

Interval Notation:

$[- 8, \infty)$

Solve the Inequality for z z/-2-6<=-2

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