Solve the Matrix Equation [[3+t,0],[8,-10]]=[[-5,0],[8,-2y+2]]

$[\begin{array}{c} 3 + t & 0 \\ 8 & - 10 \end{array}] = [\begin{array}{c} - 5 & 0 \\ 8 & - 2 y + 2 \end{array}]$

Step 1

Write as a linear system of equations.

$3 + t = - 5 0 = 0 8 = 8 - 10 = - 2 y + 2$

Step 2

Since $8 = 8$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying the system.