Solve the Rational Equation for b (b+6)/(4b^2)+3/(2b^2)=(b+4)/(2b^2)

$\frac{b + 6}{4 b^{2}} + \frac{3}{2 b^{2}} = \frac{b + 4}{2 b^{2}}$

Find the LCD of the terms in the equation.

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$4 b^{2}, 2 b^{2}, 2 b^{2}$

Since $4 b^{2}, 2 b^{2}, 2 b^{2}$ contain both numbers and variables, there are two steps to find the LCM. Find LCM for the numeric part $4, 2, 2$ then find LCM for the variable part $b^{2}, b^{2}, b^{2}$ .

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

$4$ has factors of $2$ and $2$ .

$2 \cdot 2$

Since $2$ has no factors besides $1$ and $2$ .

$2$ is a prime number

The LCM of $4, 2, 2$ is the result of multiplying all prime factors the greatest number of times they occur in either number.

$2 \cdot 2$

Multiply $2$ by $2$ .

$4$

The factors for $b^{2}$ are $b \cdot b$ , which is $b$ multiplied by each other $2$ times.

$b^{2} = b \cdot b$

$b$ occurs $2$ times.

The LCM of $b^{2}, b^{2}, b^{2}$ is the result of multiplying all prime factors the greatest number of times they occur in either term.

$b \cdot b$

Multiply $b$ by $b$ .

$b^{2}$

The LCM for $4 b^{2}, 2 b^{2}, 2 b^{2}$ is the numeric part $4$ multiplied by the variable part.

$4 b^{2}$

Multiply each term in $\frac{b + 6}{4 b^{2}} + \frac{3}{2 b^{2}} = \frac{b + 4}{2 b^{2}}$ by $4 b^{2}$ to eliminate the fractions.

Multiply each term in $\frac{b + 6}{4 b^{2}} + \frac{3}{2 b^{2}} = \frac{b + 4}{2 b^{2}}$ by $4 b^{2}$ .

$\frac{b + 6}{4 b^{2}} (4 b^{2}) + \frac{3}{2 b^{2}} (4 b^{2}) = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Simplify the left side.

Simplify each term.

Rewrite using the commutative property of multiplication.

$4 \frac{b + 6}{4 b^{2}} b^{2} + \frac{3}{2 b^{2}} (4 b^{2}) = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Cancel the common factor of $4$ .

Factor $4$ out of $4 b^{2}$ .

$4 \frac{b + 6}{4 (b^{2})} b^{2} + \frac{3}{2 b^{2}} (4 b^{2}) = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Cancel the common factor.

$4 \frac{b + 6}{4 b^{2}} b^{2} + \frac{3}{2 b^{2}} (4 b^{2}) = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Rewrite the expression.

$\frac{b + 6}{b^{2}} b^{2} + \frac{3}{2 b^{2}} (4 b^{2}) = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Cancel the common factor of $b^{2}$ .

Cancel the common factor.

$\frac{b + 6}{b^{2}} b^{2} + \frac{3}{2 b^{2}} (4 b^{2}) = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Rewrite the expression.

$b + 6 + \frac{3}{2 b^{2}} (4 b^{2}) = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Rewrite using the commutative property of multiplication.

$b + 6 + 4 \frac{3}{2 b^{2}} b^{2} = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$b + 6 + 2 (2) \frac{3}{2 b^{2}} b^{2} = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Factor $2$ out of $2 b^{2}$ .

$b + 6 + 2 (2) \frac{3}{2 (b^{2})} b^{2} = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Cancel the common factor.

$b + 6 + 2 \cdot 2 \frac{3}{2 b^{2}} b^{2} = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Rewrite the expression.

$b + 6 + 2 \frac{3}{b^{2}} b^{2} = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Combine $2$ and $\frac{3}{b^{2}}$ .

$b + 6 + \frac{2 \cdot 3}{b^{2}} b^{2} = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Multiply $2$ by $3$ .

$b + 6 + \frac{6}{b^{2}} b^{2} = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Cancel the common factor of $b^{2}$ .

Cancel the common factor.

$b + 6 + \frac{6}{b^{2}} b^{2} = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Rewrite the expression.

$b + 6 + 6 = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Add $6$ and $6$ .

$b + 12 = \frac{b + 4}{2 b^{2}} (4 b^{2})$

Simplify the right side.

Rewrite using the commutative property of multiplication.

$b + 12 = 4 \frac{b + 4}{2 b^{2}} b^{2}$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$b + 12 = 2 (2) \frac{b + 4}{2 b^{2}} b^{2}$

Factor $2$ out of $2 b^{2}$ .

$b + 12 = 2 (2) \frac{b + 4}{2 (b^{2})} b^{2}$

Cancel the common factor.

$b + 12 = 2 \cdot 2 \frac{b + 4}{2 b^{2}} b^{2}$

Rewrite the expression.

$b + 12 = 2 \frac{b + 4}{b^{2}} b^{2}$

Combine $2$ and $\frac{b + 4}{b^{2}}$ .

$b + 12 = \frac{2 (b + 4)}{b^{2}} b^{2}$

Cancel the common factor of $b^{2}$ .

Cancel the common factor.

$b + 12 = \frac{2 (b + 4)}{b^{2}} b^{2}$

Rewrite the expression.

$b + 12 = 2 (b + 4)$

Apply the distributive property.

$b + 12 = 2 b + 2 \cdot 4$

Multiply $2$ by $4$ .

$b + 12 = 2 b + 8$

Solve the equation.

Move all terms containing $b$ to the left side of the equation.

Subtract $2 b$ from both sides of the equation.

$b + 12 - 2 b = 8$

Subtract $2 b$ from $b$ .

$- b + 12 = 8$

Move all terms not containing $b$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$- b = 8 - 12$

Subtract $12$ from $8$ .

$- b = - 4$

Divide each term in $- b = - 4$ by $- 1$ and simplify.

Divide each term in $- b = - 4$ by $- 1$ .

$\frac{- b}{- 1} = \frac{- 4}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{b}{1} = \frac{- 4}{- 1}$

Divide $b$ by $1$ .

$b = \frac{- 4}{- 1}$

Simplify the right side.

Divide $- 4$ by $- 1$ .

$b = 4$

Solve the Rational Equation for b (b+6)/(4b^2)+3/(2b^2)=(b+4)/(2b^2)

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