Solve the Rational Equation for x square root of x-3- square root of x=3

$\sqrt{x - 3} - \sqrt{x} = 3$

Add $\sqrt{x}$ to both sides of the equation.

$\sqrt{x - 3} = 3 + \sqrt{x}$

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{x - 3}}^{2} = {(3 + \sqrt{x})}^{2}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x - 3}$ as ${(x - 3)}^{\frac{1}{2}}$ .

${({(x - 3)}^{\frac{1}{2}})}^{2} = {(3 + \sqrt{x})}^{2}$

Simplify the left side.

Simplify ${({(x - 3)}^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${({(x - 3)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

${(x - 3)}^{\frac{1}{2} \cdot 2} = {(3 + \sqrt{x})}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

${(x - 3)}^{\frac{1}{2} \cdot 2} = {(3 + \sqrt{x})}^{2}$

Rewrite the expression.

${(x - 3)}^{1} = {(3 + \sqrt{x})}^{2}$

Simplify.

$x - 3 = {(3 + \sqrt{x})}^{2}$

Simplify the right side.

Simplify ${(3 + \sqrt{x})}^{2}$ .

Rewrite ${(3 + \sqrt{x})}^{2}$ as $(3 + \sqrt{x}) (3 + \sqrt{x})$ .

$x - 3 = (3 + \sqrt{x}) (3 + \sqrt{x})$

Expand $(3 + \sqrt{x}) (3 + \sqrt{x})$ using the FOIL Method.

Apply the distributive property.

$x - 3 = 3 (3 + \sqrt{x}) + \sqrt{x} (3 + \sqrt{x})$

Apply the distributive property.

$x - 3 = 3 \cdot 3 + 3 \sqrt{x} + \sqrt{x} (3 + \sqrt{x})$

Apply the distributive property.

$x - 3 = 3 \cdot 3 + 3 \sqrt{x} + \sqrt{x} \cdot 3 + \sqrt{x} \sqrt{x}$

Simplify and combine like terms.

Simplify each term.

Multiply $3$ by $3$ .

$x - 3 = 9 + 3 \sqrt{x} + \sqrt{x} \cdot 3 + \sqrt{x} \sqrt{x}$

Move $3$ to the left of $\sqrt{x}$ .

$x - 3 = 9 + 3 \sqrt{x} + 3 \cdot \sqrt{x} + \sqrt{x} \sqrt{x}$

Multiply $\sqrt{x} \sqrt{x}$ .

Raise $\sqrt{x}$ to the power of $1$ .

$x - 3 = 9 + 3 \sqrt{x} + 3 \sqrt{x} + {\sqrt{x}}^{1} \sqrt{x}$

Raise $\sqrt{x}$ to the power of $1$ .

$x - 3 = 9 + 3 \sqrt{x} + 3 \sqrt{x} + {\sqrt{x}}^{1} {\sqrt{x}}^{1}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 3 = 9 + 3 \sqrt{x} + 3 \sqrt{x} + {\sqrt{x}}^{1 + 1}$

Add $1$ and $1$ .

$x - 3 = 9 + 3 \sqrt{x} + 3 \sqrt{x} + {\sqrt{x}}^{2}$

Rewrite ${\sqrt{x}}^{2}$ as $x$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

$x - 3 = 9 + 3 \sqrt{x} + 3 \sqrt{x} + {(x^{\frac{1}{2}})}^{2}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x - 3 = 9 + 3 \sqrt{x} + 3 \sqrt{x} + x^{\frac{1}{2} \cdot 2}$

Combine $\frac{1}{2}$ and $2$ .

$x - 3 = 9 + 3 \sqrt{x} + 3 \sqrt{x} + x^{\frac{2}{2}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$x - 3 = 9 + 3 \sqrt{x} + 3 \sqrt{x} + x^{\frac{2}{2}}$

Rewrite the expression.

$x - 3 = 9 + 3 \sqrt{x} + 3 \sqrt{x} + x^{1}$

Simplify.

$x - 3 = 9 + 3 \sqrt{x} + 3 \sqrt{x} + x$

Add $3 \sqrt{x}$ and $3 \sqrt{x}$ .

$x - 3 = 9 + 6 \sqrt{x} + x$

Solve for $6 \sqrt{x}$ .

Rewrite the equation as $9 + 6 \sqrt{x} + x = x - 3$ .

$9 + 6 \sqrt{x} + x = x - 3$

Move all terms not containing $6 \sqrt{x}$ to the right side of the equation.

Subtract $9$ from both sides of the equation.

$6 \sqrt{x} + x = x - 3 - 9$

Subtract $x$ from both sides of the equation.

$6 \sqrt{x} = x - 3 - 9 - x$

Combine the opposite terms in $x - 3 - 9 - x$ .

Subtract $x$ from $x$ .

$6 \sqrt{x} = 0 - 3 - 9$

Subtract $3$ from $0$ .

$6 \sqrt{x} = - 3 - 9$

Subtract $9$ from $- 3$ .

$6 \sqrt{x} = - 12$

To remove the radical on the left side of the equation, square both sides of the equation.

${(6 \sqrt{x})}^{2} = {(- 12)}^{2}$

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x}$ as $x^{\frac{1}{2}}$ .

${(6 x^{\frac{1}{2}})}^{2} = {(- 12)}^{2}$

Simplify the left side.

Simplify ${(6 x^{\frac{1}{2}})}^{2}$ .

Apply the product rule to $6 x^{\frac{1}{2}}$ .

$6^{2} {(x^{\frac{1}{2}})}^{2} = {(- 12)}^{2}$

Raise $6$ to the power of $2$ .

$36 {(x^{\frac{1}{2}})}^{2} = {(- 12)}^{2}$

Multiply the exponents in ${(x^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$36 x^{\frac{1}{2} \cdot 2} = {(- 12)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$36 x^{\frac{1}{2} \cdot 2} = {(- 12)}^{2}$

Rewrite the expression.

$36 x^{1} = {(- 12)}^{2}$

Simplify.

$36 x = {(- 12)}^{2}$

Simplify the right side.

Raise $- 12$ to the power of $2$ .

$36 x = 144$

Divide each term in $36 x = 144$ by $36$ and simplify.

Divide each term in $36 x = 144$ by $36$ .

$\frac{36 x}{36} = \frac{144}{36}$

Simplify the left side.

Cancel the common factor of $36$ .

Cancel the common factor.

$\frac{36 x}{36} = \frac{144}{36}$

Divide $x$ by $1$ .

$x = \frac{144}{36}$

Simplify the right side.

Divide $144$ by $36$ .

$x = 4$

Exclude the solutions that do not make $\sqrt{x - 3} - \sqrt{x} = 3$ true.

$No solution$

Solve the Rational Equation for x square root of x-3- square root of x=3

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