Solve the System of Equations 11x-20y=28 3x+4y=36

$11 x - 20 y = 28$ $3 x + 4 y = 36$

Solve for $x$ in $11 x - 20 y = 28$ .

Add $20 y$ to both sides of the equation.

$11 x = 28 + 20 y$

$3 x + 4 y = 36$

Divide each term in $11 x = 28 + 20 y$ by $11$ and simplify.

Divide each term in $11 x = 28 + 20 y$ by $11$ .

$\frac{11 x}{11} = \frac{28}{11} + \frac{20 y}{11}$

$3 x + 4 y = 36$

Simplify the left side.

Cancel the common factor of $11$ .

Cancel the common factor.

$\frac{11 x}{11} = \frac{28}{11} + \frac{20 y}{11}$

$3 x + 4 y = 36$

Divide $x$ by $1$ .

$x = \frac{28}{11} + \frac{20 y}{11}$

$3 x + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$3 x + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$3 x + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$3 x + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$3 x + 4 y = 36$

Replace all occurrences of $x$ with $\frac{28}{11} + \frac{20 y}{11}$ in each equation.

Replace all occurrences of $x$ in $3 x + 4 y = 36$ with $\frac{28}{11} + \frac{20 y}{11}$ .

$3 (\frac{28}{11} + \frac{20 y}{11}) + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Simplify the left side.

Simplify $3 (\frac{28}{11} + \frac{20 y}{11}) + 4 y$ .

Simplify each term.

Apply the distributive property.

$3 (\frac{28}{11}) + 3 (\frac{20 y}{11}) + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Multiply $3 (\frac{28}{11})$ .

Combine $3$ and $\frac{28}{11}$ .

$\frac{3 \cdot 28}{11} + 3 (\frac{20 y}{11}) + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Multiply $3$ by $28$ .

$\frac{84}{11} + 3 (\frac{20 y}{11}) + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$\frac{84}{11} + 3 (\frac{20 y}{11}) + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Multiply $3 \frac{20 y}{11}$ .

Combine $3$ and $\frac{20 y}{11}$ .

$\frac{84}{11} + \frac{3 (20 y)}{11} + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Multiply $20$ by $3$ .

$\frac{84}{11} + \frac{60 y}{11} + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$\frac{84}{11} + \frac{60 y}{11} + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$\frac{84}{11} + \frac{60 y}{11} + 4 y = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

To write $4 y$ as a fraction with a common denominator, multiply by $\frac{11}{11}$ .

$\frac{84}{11} + \frac{60 y}{11} + 4 y \cdot \frac{11}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Combine $4 y$ and $\frac{11}{11}$ .

$\frac{84}{11} + \frac{60 y}{11} + \frac{4 y \cdot 11}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Combine the numerators over the common denominator.

$\frac{84}{11} + \frac{60 y + 4 y \cdot 11}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Combine the numerators over the common denominator.

$\frac{84 + 60 y + 4 y \cdot 11}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Multiply $11$ by $4$ .

$\frac{84 + 60 y + 44 y}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Add $60 y$ and $44 y$ .

$\frac{84 + 104 y}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Factor $4$ out of $84 + 104 y$ .

Factor $4$ out of $84$ .

$\frac{4 (21) + 104 y}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Factor $4$ out of $104 y$ .

$\frac{4 (21) + 4 (26 y)}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Factor $4$ out of $4 (21) + 4 (26 y)$ .

$\frac{4 (21 + 26 y)}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$\frac{4 (21 + 26 y)}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$\frac{4 (21 + 26 y)}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$\frac{4 (21 + 26 y)}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

$\frac{4 (21 + 26 y)}{11} = 36$

$x = \frac{28}{11} + \frac{20 y}{11}$

Solve for $y$ in $\frac{4 (21 + 26 y)}{11} = 36$ .

Multiply both sides by $11$ .

$\frac{4 (21 + 26 y)}{11} \cdot 11 = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

Simplify.

Simplify the left side.

Simplify $\frac{4 (21 + 26 y)}{11} \cdot 11$ .

Cancel the common factor of $11$ .

Cancel the common factor.

$\frac{4 (21 + 26 y)}{11} \cdot 11 = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

Rewrite the expression.

$4 (21 + 26 y) = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

$4 (21 + 26 y) = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

Apply the distributive property.

$4 \cdot 21 + 4 (26 y) = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

Simplify the expression.

Multiply $4$ by $21$ .

$84 + 4 (26 y) = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

Multiply $26$ by $4$ .

$84 + 104 y = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

Reorder $84$ and $104 y$ .

$104 y + 84 = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

$104 y + 84 = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

$104 y + 84 = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

$104 y + 84 = 36 \cdot 11$

$x = \frac{28}{11} + \frac{20 y}{11}$

Simplify the right side.

Multiply $36$ by $11$ .

$104 y + 84 = 396$

$x = \frac{28}{11} + \frac{20 y}{11}$

$104 y + 84 = 396$

$x = \frac{28}{11} + \frac{20 y}{11}$

$104 y + 84 = 396$

$x = \frac{28}{11} + \frac{20 y}{11}$

Solve for $y$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $84$ from both sides of the equation.

$104 y = 396 - 84$

$x = \frac{28}{11} + \frac{20 y}{11}$

Subtract $84$ from $396$ .

$104 y = 312$

$x = \frac{28}{11} + \frac{20 y}{11}$

$104 y = 312$

$x = \frac{28}{11} + \frac{20 y}{11}$

Divide each term in $104 y = 312$ by $104$ and simplify.

Divide each term in $104 y = 312$ by $104$ .

$\frac{104 y}{104} = \frac{312}{104}$

$x = \frac{28}{11} + \frac{20 y}{11}$

Simplify the left side.

Cancel the common factor of $104$ .

Cancel the common factor.

$\frac{104 y}{104} = \frac{312}{104}$

$x = \frac{28}{11} + \frac{20 y}{11}$

Divide $y$ by $1$ .

$y = \frac{312}{104}$

$x = \frac{28}{11} + \frac{20 y}{11}$

$y = \frac{312}{104}$

$x = \frac{28}{11} + \frac{20 y}{11}$

$y = \frac{312}{104}$

$x = \frac{28}{11} + \frac{20 y}{11}$

Simplify the right side.

Divide $312$ by $104$ .

$y = 3$

$x = \frac{28}{11} + \frac{20 y}{11}$

$y = 3$

$x = \frac{28}{11} + \frac{20 y}{11}$

$y = 3$

$x = \frac{28}{11} + \frac{20 y}{11}$

$y = 3$

$x = \frac{28}{11} + \frac{20 y}{11}$

$y = 3$

$x = \frac{28}{11} + \frac{20 y}{11}$

Replace all occurrences of $y$ with $3$ in each equation.

Replace all occurrences of $y$ in $x = \frac{28}{11} + \frac{20 y}{11}$ with $3$ .

$x = \frac{28}{11} + \frac{20 (3)}{11}$

$y = 3$

Simplify the right side.

Simplify $\frac{28}{11} + \frac{20 (3)}{11}$ .

Combine the numerators over the common denominator.

$x = \frac{28 + 20 (3)}{11}$

$y = 3$

Simplify the expression.

Multiply $20$ by $3$ .

$x = \frac{28 + 60}{11}$

$y = 3$

Add $28$ and $60$ .

$x = \frac{88}{11}$

$y = 3$

Divide $88$ by $11$ .

$x = 8$

$y = 3$

$x = 8$

$y = 3$

$x = 8$

$y = 3$

$x = 8$

$y = 3$

$x = 8$

$y = 3$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(8, 3)$

The result can be shown in multiple forms.

Point Form:

$(8, 3)$

Equation Form:

$x = 8, y = 3$

Solve the System of Equations 11x-20y=28 3x+4y=36

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