Solve the System of Equations 14x+7y=-7 y=-2x-1

$14 x + 7 y = - 7$ $y = - 2 x - 1$

Step 1

Replace all occurrences of $y$ with $- 2 x - 1$ in each equation.

Replace all occurrences of $y$ in $14 x + 7 y = - 7$ with $- 2 x - 1$ .

$14 x + 7 (- 2 x - 1) = - 7$

$y = - 2 x - 1$

Simplify the left side.

Simplify $14 x + 7 (- 2 x - 1)$ .

Simplify each term.

Apply the distributive property.

$14 x + 7 (- 2 x) + 7 \cdot - 1 = - 7$

$y = - 2 x - 1$

Multiply $- 2$ by $7$ .

$14 x - 14 x + 7 \cdot - 1 = - 7$

$y = - 2 x - 1$

Multiply $7$ by $- 1$ .

$14 x - 14 x - 7 = - 7$

$y = - 2 x - 1$

$14 x - 14 x - 7 = - 7$

$y = - 2 x - 1$

Simplify by adding terms.

Subtract $14 x$ from $14 x$ .

$0 - 7 = - 7$

$y = - 2 x - 1$

Subtract $7$ from $0$ .

$- 7 = - 7$

$y = - 2 x - 1$

$- 7 = - 7$

$y = - 2 x - 1$

$- 7 = - 7$

$y = - 2 x - 1$

$- 7 = - 7$

$y = - 2 x - 1$

$- 7 = - 7$

$y = - 2 x - 1$

Step 2

Remove any equations from the system that are always true.

$y = - 2 x - 1$

Step 3

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