Solve the System of Equations 20x-5y=5 4x-y=1

$20 x - 5 y = 5$ $4 x - y = 1$

Solve for $x$ in $20 x - 5 y = 5$ .

Add $5 y$ to both sides of the equation.

$20 x = 5 + 5 y$

$4 x - y = 1$

Divide each term in $20 x = 5 + 5 y$ by $20$ and simplify.

Divide each term in $20 x = 5 + 5 y$ by $20$ .

$\frac{20 x}{20} = \frac{5}{20} + \frac{5 y}{20}$

$4 x - y = 1$

Simplify the left side.

Cancel the common factor of $20$ .

Cancel the common factor.

$\frac{20 x}{20} = \frac{5}{20} + \frac{5 y}{20}$

$4 x - y = 1$

Divide $x$ by $1$ .

$x = \frac{5}{20} + \frac{5 y}{20}$

$4 x - y = 1$

$x = \frac{5}{20} + \frac{5 y}{20}$

$4 x - y = 1$

$x = \frac{5}{20} + \frac{5 y}{20}$

$4 x - y = 1$

Simplify the right side.

Simplify each term.

Cancel the common factor of $5$ and $20$ .

Factor $5$ out of $5$ .

$x = \frac{5 (1)}{20} + \frac{5 y}{20}$

$4 x - y = 1$

Cancel the common factors.

Factor $5$ out of $20$ .

$x = \frac{5 \cdot 1}{5 \cdot 4} + \frac{5 y}{20}$

$4 x - y = 1$

Cancel the common factor.

$x = \frac{5 \cdot 1}{5 \cdot 4} + \frac{5 y}{20}$

$4 x - y = 1$

Rewrite the expression.

$x = \frac{1}{4} + \frac{5 y}{20}$

$4 x - y = 1$

$x = \frac{1}{4} + \frac{5 y}{20}$

$4 x - y = 1$

$x = \frac{1}{4} + \frac{5 y}{20}$

$4 x - y = 1$

Cancel the common factor of $5$ and $20$ .

Factor $5$ out of $5 y$ .

$x = \frac{1}{4} + \frac{5 (y)}{20}$

$4 x - y = 1$

Cancel the common factors.

Factor $5$ out of $20$ .

$x = \frac{1}{4} + \frac{5 y}{5 \cdot 4}$

$4 x - y = 1$

Cancel the common factor.

$x = \frac{1}{4} + \frac{5 y}{5 \cdot 4}$

$4 x - y = 1$

Rewrite the expression.