Solve the System of Equations 2x+y=-2 y=x-8

$2 x + y = - 2$ $y = x - 8$

Replace all occurrences of $y$ with $x - 8$ in each equation.

Replace all occurrences of $y$ in $2 x + y = - 2$ with $x - 8$ .

$2 x + x - 8 = - 2$

$y = x - 8$

Simplify the left side.

Simplify $2 x + x - 8$ .

Remove parentheses.

$2 x + x - 8 = - 2$

$y = x - 8$

Add $2 x$ and $x$ .

$3 x - 8 = - 2$

$y = x - 8$

$3 x - 8 = - 2$

$y = x - 8$

$3 x - 8 = - 2$

$y = x - 8$

$3 x - 8 = - 2$

$y = x - 8$

Solve for $x$ in $3 x - 8 = - 2$ .

Move all terms not containing $x$ to the right side of the equation.

Add $8$ to both sides of the equation.

$3 x = - 2 + 8$

$y = x - 8$

Add $- 2$ and $8$ .

$3 x = 6$

$y = x - 8$

$3 x = 6$

$y = x - 8$

Divide each term in $3 x = 6$ by $3$ and simplify.

Divide each term in $3 x = 6$ by $3$ .

$\frac{3 x}{3} = \frac{6}{3}$

$y = x - 8$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{6}{3}$

$y = x - 8$

Divide $x$ by $1$ .

$x = \frac{6}{3}$

$y = x - 8$

$x = \frac{6}{3}$

$y = x - 8$

$x = \frac{6}{3}$

$y = x - 8$

Simplify the right side.

Divide $6$ by $3$ .

$x = 2$

$y = x - 8$

$x = 2$

$y = x - 8$

$x = 2$

$y = x - 8$

$x = 2$

$y = x - 8$

Replace all occurrences of $x$ with $2$ in each equation.

Replace all occurrences of $x$ in $y = x - 8$ with $2$ .

$y = (2) - 8$

$x = 2$

Simplify the right side.

Subtract $8$ from $2$ .

$y = - 6$

$x = 2$

$y = - 6$

$x = 2$

$y = - 6$

$x = 2$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, - 6)$

The result can be shown in multiple forms.

Point Form:

$(2, - 6)$

Equation Form:

$x = 2, y = - 6$

Solve the System of Equations 2x+y=-2 y=x-8

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