Solve the System of Equations -3/4x+1/2y=-2 1/5x-1/4y=-6

$- \frac{3}{4} x + \frac{1}{2} y = - 2$ $\frac{1}{5} x - \frac{1}{4} y = - 6$

Step 1

Solve for $x$ in $- \frac{3}{4} x + \frac{1}{2} y = - 2$ .

Simplify each term.

Combine $x$ and $\frac{3}{4}$ .

$- \frac{x \cdot 3}{4} + \frac{1}{2} y = - 2$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Move $3$ to the left of $x$ .

$- \frac{3 \cdot x}{4} + \frac{1}{2} y = - 2$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Combine $\frac{1}{2}$ and $y$ .

$- \frac{3 x}{4} + \frac{y}{2} = - 2$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$- \frac{3 x}{4} + \frac{y}{2} = - 2$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Subtract $\frac{y}{2}$ from both sides of the equation.

$- \frac{3 x}{4} = - 2 - \frac{y}{2}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Multiply both sides of the equation by $- \frac{4}{3}$ .

$- \frac{4}{3} \cdot (- \frac{3 x}{4}) = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{4}{3} (- \frac{3 x}{4})$ .

Cancel the common factor of $4$ .

Move the leading negative in $- \frac{4}{3}$ into the numerator.

$\frac{- 4}{3} \cdot (- \frac{3 x}{4}) = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Move the leading negative in $- \frac{3 x}{4}$ into the numerator.

$\frac{- 4}{3} \cdot \frac{- 3 x}{4} = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Factor $4$ out of $- 4$ .

$\frac{4 (- 1)}{3} \cdot \frac{- 3 x}{4} = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Cancel the common factor.

$\frac{4 \cdot - 1}{3} \cdot \frac{- 3 x}{4} = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Rewrite the expression.

$\frac{- 1}{3} \cdot (- 3 x) = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$\frac{- 1}{3} \cdot (- 3 x) = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Cancel the common factor of $3$ .

Factor $3$ out of $- 3 x$ .

$\frac{- 1}{3} \cdot (3 (- x)) = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Cancel the common factor.

$\frac{- 1}{3} \cdot (3 (- x)) = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Rewrite the expression.

$x = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Multiply $x$ by $1$ .

$x = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = - \frac{4}{3} \cdot (- 2 - \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Simplify the right side.

Simplify $- \frac{4}{3} (- 2 - \frac{y}{2})$ .

Apply the distributive property.

$x = - \frac{4}{3} \cdot - 2 - \frac{4}{3} \cdot (- \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Multiply $- \frac{4}{3} \cdot - 2$ .

Multiply $- 2$ by $- 1$ .

$x = 2 (\frac{4}{3}) - \frac{4}{3} \cdot (- \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Combine $2$ and $\frac{4}{3}$ .

$x = \frac{2 \cdot 4}{3} - \frac{4}{3} \cdot (- \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Multiply $2$ by $4$ .

$x = \frac{8}{3} - \frac{4}{3} \cdot (- \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = \frac{8}{3} - \frac{4}{3} \cdot (- \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Simplify terms.

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{4}{3}$ into the numerator.

$x = \frac{8}{3} + \frac{- 4}{3} \cdot (- \frac{y}{2})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Move the leading negative in $- \frac{y}{2}$ into the numerator.

$x = \frac{8}{3} + \frac{- 4}{3} \cdot \frac{- y}{2}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Factor $2$ out of $- 4$ .

$x = \frac{8}{3} + \frac{2 (- 2)}{3} \cdot \frac{- y}{2}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Cancel the common factor.

$x = \frac{8}{3} + \frac{2 \cdot - 2}{3} \cdot \frac{- y}{2}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Rewrite the expression.

$x = \frac{8}{3} + \frac{- 2}{3} \cdot (- y)$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = \frac{8}{3} + \frac{- 2}{3} \cdot (- y)$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Combine $\frac{- 2}{3}$ and $y$ .

$x = \frac{8}{3} - \frac{- 2 y}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = \frac{8}{3} - \frac{- 2 y}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Simplify each term.

Move the negative in front of the fraction.

$x = \frac{8}{3} + \frac{(2) y}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Multiply $- - \frac{2 y}{3}$ .

Multiply $- 1$ by $- 1$ .

$x = \frac{8}{3} + 1 (\frac{2 y}{3})$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Multiply $\frac{2 y}{3}$ by $1$ .

$x = \frac{8}{3} + \frac{2 y}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = \frac{8}{3} + \frac{2 y}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = \frac{8}{3} + \frac{2 y}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = \frac{8}{3} + \frac{2 y}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = \frac{8}{3} + \frac{2 y}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = \frac{8}{3} + \frac{2 y}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Reorder $\frac{8}{3}$ and $\frac{2 y}{3}$ .

$x = \frac{2 y}{3} + \frac{8}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$\frac{1}{5} x - \frac{1}{4} y = - 6$

Step 2

Replace all occurrences of $x$ with $\frac{2 y}{3} + \frac{8}{3}$ in each equation.

Replace all occurrences of $x$ in $\frac{1}{5} x - \frac{1}{4} y = - 6$ with $\frac{2 y}{3} + \frac{8}{3}$ .

$\frac{1}{5} \cdot (\frac{2 y}{3} + \frac{8}{3}) - \frac{1}{4} y = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Simplify the left side.

Simplify $\frac{1}{5} \cdot (\frac{2 y}{3} + \frac{8}{3}) - \frac{1}{4} y$ .

Simplify each term.

Apply the distributive property.

$\frac{1}{5} \cdot \frac{2 y}{3} + \frac{1}{5} \cdot \frac{8}{3} - \frac{1}{4} y = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $\frac{1}{5} \cdot \frac{2 y}{3}$ .

Multiply $\frac{1}{5}$ by $\frac{2 y}{3}$ .

$\frac{2 y}{5 \cdot 3} + \frac{1}{5} \cdot \frac{8}{3} - \frac{1}{4} y = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $5$ by $3$ .

$\frac{2 y}{15} + \frac{1}{5} \cdot \frac{8}{3} - \frac{1}{4} y = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$\frac{2 y}{15} + \frac{1}{5} \cdot \frac{8}{3} - \frac{1}{4} y = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $\frac{1}{5} \cdot \frac{8}{3}$ .

Multiply $\frac{1}{5}$ by $\frac{8}{3}$ .

$\frac{2 y}{15} + \frac{8}{5 \cdot 3} - \frac{1}{4} y = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $5$ by $3$ .

$\frac{2 y}{15} + \frac{8}{15} - \frac{1}{4} y = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$\frac{2 y}{15} + \frac{8}{15} - \frac{1}{4} y = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Combine $y$ and $\frac{1}{4}$ .

$\frac{2 y}{15} + \frac{8}{15} - \frac{y}{4} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$\frac{2 y}{15} + \frac{8}{15} - \frac{y}{4} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

To write $\frac{2 y}{15}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$\frac{2 y}{15} \cdot \frac{4}{4} - \frac{y}{4} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

To write $- \frac{y}{4}$ as a fraction with a common denominator, multiply by $\frac{15}{15}$ .

$\frac{2 y}{15} \cdot \frac{4}{4} - \frac{y}{4} \cdot \frac{15}{15} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Write each expression with a common denominator of $60$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{2 y}{15}$ by $\frac{4}{4}$ .

$\frac{2 y \cdot 4}{15 \cdot 4} - \frac{y}{4} \cdot \frac{15}{15} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $15$ by $4$ .

$\frac{2 y \cdot 4}{60} - \frac{y}{4} \cdot \frac{15}{15} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $\frac{y}{4}$ by $\frac{15}{15}$ .

$\frac{2 y \cdot 4}{60} - \frac{y \cdot 15}{4 \cdot 15} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $4$ by $15$ .

$\frac{2 y \cdot 4}{60} - \frac{y \cdot 15}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$\frac{2 y \cdot 4}{60} - \frac{y \cdot 15}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Combine the numerators over the common denominator.

$\frac{2 y \cdot 4 - y \cdot 15}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Simplify each term.

Simplify the numerator.

Factor $y$ out of $2 y \cdot 4 - y \cdot 15$ .

Factor $y$ out of $2 y \cdot 4$ .

$\frac{y (2 \cdot 4) - y \cdot 15}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Factor $y$ out of $- y \cdot 15$ .

$\frac{y (2 \cdot 4) + y (- 1 \cdot 15)}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Factor $y$ out of $y (2 \cdot 4) + y (- 1 \cdot 15)$ .

$\frac{y (2 \cdot 4 - 1 \cdot 15)}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$\frac{y (2 \cdot 4 - 1 \cdot 15)}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $2$ by $4$ .

$\frac{y (8 - 1 \cdot 15)}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $- 1$ by $15$ .

$\frac{y (8 - 15)}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Subtract $15$ from $8$ .

$\frac{y \cdot - 7}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$\frac{y \cdot - 7}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Move $- 7$ to the left of $y$ .

$\frac{- 7 \cdot y}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Move the negative in front of the fraction.

$- \frac{7 y}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$- \frac{7 y}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$- \frac{7 y}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$- \frac{7 y}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

$- \frac{7 y}{60} + \frac{8}{15} = - 6$

$x = \frac{2 y}{3} + \frac{8}{3}$

Step 3

Solve for $y$ in $- \frac{7 y}{60} + \frac{8}{15} = - 6$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $\frac{8}{15}$ from both sides of the equation.

$- \frac{7 y}{60} = - 6 - \frac{8}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

To write $- 6$ as a fraction with a common denominator, multiply by $\frac{15}{15}$ .

$- \frac{7 y}{60} = - 6 \cdot \frac{15}{15} - \frac{8}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

Combine $- 6$ and $\frac{15}{15}$ .

$- \frac{7 y}{60} = \frac{- 6 \cdot 15}{15} - \frac{8}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

Combine the numerators over the common denominator.

$- \frac{7 y}{60} = \frac{- 6 \cdot 15 - 8}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

Simplify the numerator.

Multiply $- 6$ by $15$ .

$- \frac{7 y}{60} = \frac{- 90 - 8}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

Subtract $8$ from $- 90$ .

$- \frac{7 y}{60} = \frac{- 98}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

$- \frac{7 y}{60} = \frac{- 98}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

Move the negative in front of the fraction.

$- \frac{7 y}{60} = - \frac{98}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

$- \frac{7 y}{60} = - \frac{98}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply both sides of the equation by $- \frac{60}{7}$ .

$- \frac{60}{7} \cdot (- \frac{7 y}{60}) = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{60}{7} (- \frac{7 y}{60})$ .

Cancel the common factor of $60$ .

Move the leading negative in $- \frac{60}{7}$ into the numerator.

$\frac{- 60}{7} \cdot (- \frac{7 y}{60}) = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Move the leading negative in $- \frac{7 y}{60}$ into the numerator.

$\frac{- 60}{7} \cdot \frac{- 7 y}{60} = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Factor $60$ out of $- 60$ .

$\frac{60 (- 1)}{7} \cdot \frac{- 7 y}{60} = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Cancel the common factor.

$\frac{60 \cdot - 1}{7} \cdot \frac{- 7 y}{60} = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Rewrite the expression.

$\frac{- 1}{7} \cdot (- 7 y) = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

$\frac{- 1}{7} \cdot (- 7 y) = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Cancel the common factor of $7$ .

Factor $7$ out of $- 7 y$ .

$\frac{- 1}{7} \cdot (7 (- y)) = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Cancel the common factor.

$\frac{- 1}{7} \cdot (7 (- y)) = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Rewrite the expression.

$y = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

$y = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 y = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $y$ by $1$ .

$y = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

$y = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

$y = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

$y = - \frac{60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Simplify the right side.

Simplify $- \frac{60}{7} (- \frac{98}{15})$ .

Cancel the common factor of $15$ .

Move the leading negative in $- \frac{60}{7}$ into the numerator.

$y = \frac{- 60}{7} \cdot (- \frac{98}{15})$

$x = \frac{2 y}{3} + \frac{8}{3}$

Move the leading negative in $- \frac{98}{15}$ into the numerator.

$y = \frac{- 60}{7} \cdot \frac{- 98}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

Factor $15$ out of $- 60$ .

$y = \frac{15 (- 4)}{7} \cdot \frac{- 98}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

Cancel the common factor.

$y = \frac{15 \cdot - 4}{7} \cdot \frac{- 98}{15}$

$x = \frac{2 y}{3} + \frac{8}{3}$

Rewrite the expression.

$y = \frac{- 4}{7} \cdot - 98$

$x = \frac{2 y}{3} + \frac{8}{3}$

$y = \frac{- 4}{7} \cdot - 98$

$x = \frac{2 y}{3} + \frac{8}{3}$

Cancel the common factor of $7$ .

Factor $7$ out of $- 98$ .

$y = \frac{- 4}{7} \cdot (7 (- 14))$

$x = \frac{2 y}{3} + \frac{8}{3}$

Cancel the common factor.

$y = \frac{- 4}{7} \cdot (7 \cdot - 14)$

$x = \frac{2 y}{3} + \frac{8}{3}$

Rewrite the expression.

$y = - 4 \cdot - 14$

$x = \frac{2 y}{3} + \frac{8}{3}$

$y = - 4 \cdot - 14$

$x = \frac{2 y}{3} + \frac{8}{3}$

Multiply $- 4$ by $- 14$ .

$y = 56$

$x = \frac{2 y}{3} + \frac{8}{3}$

$y = 56$

$x = \frac{2 y}{3} + \frac{8}{3}$

$y = 56$

$x = \frac{2 y}{3} + \frac{8}{3}$

$y = 56$

$x = \frac{2 y}{3} + \frac{8}{3}$

$y = 56$

$x = \frac{2 y}{3} + \frac{8}{3}$

Step 4

Replace all occurrences of $y$ with $56$ in each equation.

Replace all occurrences of $y$ in $x = \frac{2 y}{3} + \frac{8}{3}$ with $56$ .

$x = \frac{2 (56)}{3} + \frac{8}{3}$

$y = 56$

Simplify the right side.

Simplify $\frac{2 (56)}{3} + \frac{8}{3}$ .

Combine the numerators over the common denominator.

$x = \frac{2 (56) + 8}{3}$

$y = 56$

Simplify the expression.

Multiply $2$ by $56$ .

$x = \frac{112 + 8}{3}$

$y = 56$

Add $112$ and $8$ .

$x = \frac{120}{3}$

$y = 56$

Divide $120$ by $3$ .

$x = 40$

$y = 56$

$x = 40$

$y = 56$

$x = 40$

$y = 56$

$x = 40$

$y = 56$

$x = 40$

$y = 56$

Step 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(40, 56)$

Step 6

The result can be shown in multiple forms.

Point Form:

$(40, 56)$

Equation Form:

$x = 40, y = 56$

Step 7

Solve the System of Equations -3/4x+1/2y=-2 1/5x-1/4y=-6

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