Solve the System of Equations 3x=-12y+15 and x+4y=5

$3 x = - 12 y + 15$ and $x + 4 y = 5$

Divide each term in $3 x = - 12 y + 15$ by $3$ and simplify.

Divide each term in $3 x = - 12 y + 15$ by $3$ .

$\frac{3 x}{3} = \frac{- 12 y}{3} + \frac{15}{3}$

$x + 4 y = 5$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{- 12 y}{3} + \frac{15}{3}$

$x + 4 y = 5$

Divide $x$ by $1$ .

$x = \frac{- 12 y}{3} + \frac{15}{3}$

$x + 4 y = 5$

$x = \frac{- 12 y}{3} + \frac{15}{3}$

$x + 4 y = 5$

$x = \frac{- 12 y}{3} + \frac{15}{3}$

$x + 4 y = 5$

Simplify the right side.

Simplify each term.

Cancel the common factor of $- 12$ and $3$ .

Factor $3$ out of $- 12 y$ .

$x = \frac{3 (- 4 y)}{3} + \frac{15}{3}$

$x + 4 y = 5$

Cancel the common factors.

Factor $3$ out of $3$ .

$x = \frac{3 (- 4 y)}{3 (1)} + \frac{15}{3}$

$x + 4 y = 5$

Cancel the common factor.

$x = \frac{3 (- 4 y)}{3 \cdot 1} + \frac{15}{3}$

$x + 4 y = 5$

Rewrite the expression.

$x = \frac{- 4 y}{1} + \frac{15}{3}$

$x + 4 y = 5$

Divide $- 4 y$ by $1$ .

$x = - 4 y + \frac{15}{3}$

$x + 4 y = 5$

$x = - 4 y + \frac{15}{3}$

$x + 4 y = 5$

$x = - 4 y + \frac{15}{3}$

$x + 4 y = 5$

Divide $15$ by $3$ .

$x = - 4 y + 5$

$x + 4 y = 5$

$x = - 4 y + 5$

$x + 4 y = 5$

$x = - 4 y + 5$

$x + 4 y = 5$

$x = - 4 y + 5$

$x + 4 y = 5$

Replace all occurrences of $x$ with $- 4 y + 5$ in each equation.

Replace all occurrences of $x$ in $x + 4 y = 5$ with $- 4 y + 5$ .

$(- 4 y + 5) + 4 y = 5$

$x = - 4 y + 5$

Simplify the left side.

Combine the opposite terms in $(- 4 y + 5) + 4 y$ .

Add $- 4 y$ and $4 y$ .

$0 + 5 = 5$

$x = - 4 y + 5$

Add $0$ and $5$ .

$5 = 5$

$x = - 4 y + 5$

$5 = 5$

$x = - 4 y + 5$

$5 = 5$

$x = - 4 y + 5$

$5 = 5$

$x = - 4 y + 5$

Remove any equations from the system that are always true.

$x = - 4 y + 5$

Solve the System of Equations 3x=-12y+15 and x+4y=5

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