Solve the System of Equations -3x=3-y 2y=6x+6

$- 3 x = 3 - y$ $2 y = 6 x + 6$

Divide each term in $- 3 x = 3 - y$ by $- 3$ and simplify.

Divide each term in $- 3 x = 3 - y$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{3}{- 3} + \frac{- y}{- 3}$

$2 y = 6 x + 6$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{3}{- 3} + \frac{- y}{- 3}$

$2 y = 6 x + 6$

Divide $x$ by $1$ .

$x = \frac{3}{- 3} + \frac{- y}{- 3}$

$2 y = 6 x + 6$

$x = \frac{3}{- 3} + \frac{- y}{- 3}$

$2 y = 6 x + 6$

$x = \frac{3}{- 3} + \frac{- y}{- 3}$

$2 y = 6 x + 6$

Simplify the right side.

Simplify each term.

Divide $3$ by $- 3$ .

$x = - 1 + \frac{- y}{- 3}$

$2 y = 6 x + 6$

Dividing two negative values results in a positive value.

$x = - 1 + \frac{y}{3}$

$2 y = 6 x + 6$

$x = - 1 + \frac{y}{3}$

$2 y = 6 x + 6$

$x = - 1 + \frac{y}{3}$

$2 y = 6 x + 6$

$x = - 1 + \frac{y}{3}$

$2 y = 6 x + 6$

Replace all occurrences of $x$ with $- 1 + \frac{y}{3}$ in each equation.

Replace all occurrences of $x$ in $2 y = 6 x + 6$ with $- 1 + \frac{y}{3}$ .

$2 y = 6 (- 1 + \frac{y}{3}) + 6$

$x = - 1 + \frac{y}{3}$

Simplify the right side.

Simplify $6 (- 1 + \frac{y}{3}) + 6$ .

Simplify each term.

Apply the distributive property.

$2 y = 6 \cdot - 1 + 6 (\frac{y}{3}) + 6$

$x = - 1 + \frac{y}{3}$

Multiply $6$ by $- 1$ .

$2 y = - 6 + 6 (\frac{y}{3}) + 6$

$x = - 1 + \frac{y}{3}$

Cancel the common factor of $3$ .

Factor $3$ out of $6$ .

$2 y = - 6 + 3 (2) (\frac{y}{3}) + 6$

$x = - 1 + \frac{y}{3}$

Cancel the common factor.

$2 y = - 6 + 3 \cdot (2 (\frac{y}{3})) + 6$

$x = - 1 + \frac{y}{3}$

Rewrite the expression.

$2 y = - 6 + 2 y + 6$

$x = - 1 + \frac{y}{3}$

$2 y = - 6 + 2 y + 6$

$x = - 1 + \frac{y}{3}$

$2 y = - 6 + 2 y + 6$

$x = - 1 + \frac{y}{3}$

Combine the opposite terms in $- 6 + 2 y + 6$ .

Add $- 6$ and $6$ .

$2 y = 2 y + 0$

$x = - 1 + \frac{y}{3}$

Add $2 y$ and $0$ .

$2 y = 2 y$

$x = - 1 + \frac{y}{3}$

$2 y = 2 y$

$x = - 1 + \frac{y}{3}$

$2 y = 2 y$

$x = - 1 + \frac{y}{3}$

$2 y = 2 y$

$x = - 1 + \frac{y}{3}$

$2 y = 2 y$

$x = - 1 + \frac{y}{3}$

Remove any equations from the system that are always true.

$x = - 1 + \frac{y}{3}$

Solve the System of Equations -3x=3-y 2y=6x+6

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