Solve the System of Equations 3x-y=7 y+4=2(x+5)^2

$3 x - y = 7$ $y + 4 = 2 {(x + 5)}^{2}$

Solve for $x$ in $3 x - y = 7$ .

Add $y$ to both sides of the equation.

$3 x = 7 + y$

$y + 4 = 2 {(x + 5)}^{2}$

Divide each term in $3 x = 7 + y$ by $3$ and simplify.

Divide each term in $3 x = 7 + y$ by $3$ .

$\frac{3 x}{3} = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 {(x + 5)}^{2}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 {(x + 5)}^{2}$

Divide $x$ by $1$ .

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 {(x + 5)}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 {(x + 5)}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 {(x + 5)}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 {(x + 5)}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 {(x + 5)}^{2}$

Replace all occurrences of $x$ with $\frac{7}{3} + \frac{y}{3}$ in each equation.

Replace all occurrences of $x$ in $y + 4 = 2 {(x + 5)}^{2}$ with $\frac{7}{3} + \frac{y}{3}$ .

$y + 4 = 2 {((\frac{7}{3} + \frac{y}{3}) + 5)}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

Simplify the right side.

Simplify $2 {((\frac{7}{3} + \frac{y}{3}) + 5)}^{2}$ .

To write $5$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$y + 4 = 2 {(\frac{y}{3} + \frac{7}{3} + 5 \cdot \frac{3}{3})}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

Combine $5$ and $\frac{3}{3}$ .

$y + 4 = 2 {(\frac{y}{3} + \frac{7}{3} + \frac{5 \cdot 3}{3})}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

Combine the numerators over the common denominator.

$y + 4 = 2 {(\frac{y}{3} + \frac{7 + 5 \cdot 3}{3})}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

Simplify the numerator.

Multiply $5$ by $3$ .

$y + 4 = 2 {(\frac{y}{3} + \frac{7 + 15}{3})}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

Add $7$ and $15$ .

$y + 4 = 2 {(\frac{y}{3} + \frac{22}{3})}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 {(\frac{y}{3} + \frac{22}{3})}^{2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite ${(\frac{y}{3} + \frac{22}{3})}^{2}$ as $(\frac{y}{3} + \frac{22}{3}) (\frac{y}{3} + \frac{22}{3})$ .

$y + 4 = 2 ((\frac{y}{3} + \frac{22}{3}) (\frac{y}{3} + \frac{22}{3}))$

$x = \frac{7}{3} + \frac{y}{3}$

Expand $(\frac{y}{3} + \frac{22}{3}) (\frac{y}{3} + \frac{22}{3})$ using the FOIL Method.

Apply the distributive property.

$y + 4 = 2 (\frac{y}{3} \cdot (\frac{y}{3} + \frac{22}{3}) + \frac{22}{3} \cdot (\frac{y}{3} + \frac{22}{3}))$

$x = \frac{7}{3} + \frac{y}{3}$

Apply the distributive property.

$y + 4 = 2 (\frac{y}{3} \cdot \frac{y}{3} + \frac{y}{3} \cdot \frac{22}{3} + \frac{22}{3} \cdot (\frac{y}{3} + \frac{22}{3}))$

$x = \frac{7}{3} + \frac{y}{3}$

Apply the distributive property.

$y + 4 = 2 (\frac{y}{3} \cdot \frac{y}{3} + \frac{y}{3} \cdot \frac{22}{3} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 (\frac{y}{3} \cdot \frac{y}{3} + \frac{y}{3} \cdot \frac{22}{3} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Simplify and combine like terms.

Simplify each term.

Multiply $\frac{y}{3} \cdot \frac{y}{3}$ .

Multiply $\frac{y}{3}$ by $\frac{y}{3}$ .

$y + 4 = 2 (\frac{y \cdot y}{3 \cdot 3} + \frac{y}{3} \cdot \frac{22}{3} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Raise $y$ to the power of $1$ .

$y + 4 = 2 (\frac{y \cdot y}{3 \cdot 3} + \frac{y}{3} \cdot \frac{22}{3} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Raise $y$ to the power of $1$ .

$y + 4 = 2 (\frac{y \cdot y}{3 \cdot 3} + \frac{y}{3} \cdot \frac{22}{3} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y + 4 = 2 (\frac{y^{1 + 1}}{3 \cdot 3} + \frac{y}{3} \cdot \frac{22}{3} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Add $1$ and $1$ .

$y + 4 = 2 (\frac{y^{2}}{3 \cdot 3} + \frac{y}{3} \cdot \frac{22}{3} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $3$ by $3$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{y}{3} \cdot \frac{22}{3} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{y}{3} \cdot \frac{22}{3} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $\frac{y}{3} \cdot \frac{22}{3}$ .

Multiply $\frac{y}{3}$ by $\frac{22}{3}$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{y \cdot 22}{3 \cdot 3} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $3$ by $3$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{y \cdot 22}{9} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{y \cdot 22}{9} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Move $22$ to the left of $y$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{22 \cdot y}{9} + \frac{22}{3} \cdot \frac{y}{3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $\frac{22}{3} \cdot \frac{y}{3}$ .

Multiply $\frac{22}{3}$ by $\frac{y}{3}$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{22 y}{9} + \frac{22 y}{3 \cdot 3} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $3$ by $3$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{22 y}{9} + \frac{22 y}{9} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{22 y}{9} + \frac{22 y}{9} + \frac{22}{3} \cdot \frac{22}{3})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $\frac{22}{3} \cdot \frac{22}{3}$ .

Multiply $\frac{22}{3}$ by $\frac{22}{3}$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{22 y}{9} + \frac{22 y}{9} + \frac{22 \cdot 22}{3 \cdot 3})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $22$ by $22$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{22 y}{9} + \frac{22 y}{9} + \frac{484}{3 \cdot 3})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $3$ by $3$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{22 y}{9} + \frac{22 y}{9} + \frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{22 y}{9} + \frac{22 y}{9} + \frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{22 y}{9} + \frac{22 y}{9} + \frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

Add $\frac{22 y}{9}$ and $\frac{22 y}{9}$ .

$y + 4 = 2 (\frac{y^{2}}{9} + 2 (\frac{22 y}{9}) + \frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 (\frac{y^{2}}{9} + 2 (\frac{22 y}{9}) + \frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $2 \frac{22 y}{9}$ .

Combine $2$ and $\frac{22 y}{9}$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{2 (22 y)}{9} + \frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $22$ by $2$ .

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{44 y}{9} + \frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = 2 (\frac{y^{2}}{9} + \frac{44 y}{9} + \frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

Apply the distributive property.

$y + 4 = 2 (\frac{y^{2}}{9}) + 2 (\frac{44 y}{9}) + 2 (\frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

Simplify.

Combine $2$ and $\frac{y^{2}}{9}$ .

$y + 4 = \frac{2 y^{2}}{9} + 2 (\frac{44 y}{9}) + 2 (\frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $2 \frac{44 y}{9}$ .

Combine $2$ and $\frac{44 y}{9}$ .

$y + 4 = \frac{2 y^{2}}{9} + \frac{2 (44 y)}{9} + 2 (\frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $44$ by $2$ .

$y + 4 = \frac{2 y^{2}}{9} + \frac{88 y}{9} + 2 (\frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = \frac{2 y^{2}}{9} + \frac{88 y}{9} + 2 (\frac{484}{9})$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $2 (\frac{484}{9})$ .

Combine $2$ and $\frac{484}{9}$ .

$y + 4 = \frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{2 \cdot 484}{9}$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $2$ by $484$ .

$y + 4 = \frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{968}{9}$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = \frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{968}{9}$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = \frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{968}{9}$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = \frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{968}{9}$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = \frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{968}{9}$

$x = \frac{7}{3} + \frac{y}{3}$

$y + 4 = \frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{968}{9}$

$x = \frac{7}{3} + \frac{y}{3}$

Solve for $y$ in $y + 4 = \frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{968}{9}$ .

Since $y$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$\frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{968}{9} = y + 4$

$x = \frac{7}{3} + \frac{y}{3}$

Move all terms containing $y$ to the left side of the equation.

Subtract $y$ from both sides of the equation.

$\frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{968}{9} - y = 4$

$x = \frac{7}{3} + \frac{y}{3}$

To write $- y$ as a fraction with a common denominator, multiply by $\frac{9}{9}$ .

$\frac{2 y^{2}}{9} + \frac{88 y}{9} - y \cdot \frac{9}{9} + \frac{968}{9} = 4$

$x = \frac{7}{3} + \frac{y}{3}$

Combine $- y$ and $\frac{9}{9}$ .

$\frac{2 y^{2}}{9} + \frac{88 y}{9} + \frac{- y \cdot 9}{9} + \frac{968}{9} = 4$

$x = \frac{7}{3} + \frac{y}{3}$

Combine the numerators over the common denominator.

$\frac{2 y^{2}}{9} + \frac{88 y - y \cdot 9}{9} + \frac{968}{9} = 4$

$x = \frac{7}{3} + \frac{y}{3}$

Combine the numerators over the common denominator.

$\frac{2 y^{2} + 88 y - y \cdot 9 + 968}{9} = 4$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $9$ by $- 1$ .

$\frac{2 y^{2} + 88 y - 9 y + 968}{9} = 4$

$x = \frac{7}{3} + \frac{y}{3}$

Subtract $9 y$ from $88 y$ .

$\frac{2 y^{2} + 79 y + 968}{9} = 4$

$x = \frac{7}{3} + \frac{y}{3}$

$\frac{2 y^{2} + 79 y + 968}{9} = 4$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply both sides by $9$ .

$\frac{2 y^{2} + 79 y + 968}{9} \cdot 9 = 4 \cdot 9$

$x = \frac{7}{3} + \frac{y}{3}$

Simplify.

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{2 y^{2} + 79 y + 968}{9} \cdot 9 = 4 \cdot 9$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite the expression.

$2 y^{2} + 79 y + 968 = 4 \cdot 9$

$x = \frac{7}{3} + \frac{y}{3}$

$2 y^{2} + 79 y + 968 = 4 \cdot 9$

$x = \frac{7}{3} + \frac{y}{3}$

$2 y^{2} + 79 y + 968 = 4 \cdot 9$

$x = \frac{7}{3} + \frac{y}{3}$

Simplify the right side.

Multiply $4$ by $9$ .

$2 y^{2} + 79 y + 968 = 36$

$x = \frac{7}{3} + \frac{y}{3}$

$2 y^{2} + 79 y + 968 = 36$

$x = \frac{7}{3} + \frac{y}{3}$

$2 y^{2} + 79 y + 968 = 36$

$x = \frac{7}{3} + \frac{y}{3}$

Solve for $y$ .

Move all terms to the left side of the equation and simplify.

Subtract $36$ from both sides of the equation.

$2 y^{2} + 79 y + 968 - 36 = 0$

$x = \frac{7}{3} + \frac{y}{3}$

Subtract $36$ from $968$ .

$2 y^{2} + 79 y + 932 = 0$

$x = \frac{7}{3} + \frac{y}{3}$

$2 y^{2} + 79 y + 932 = 0$

$x = \frac{7}{3} + \frac{y}{3}$

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

$x = \frac{7}{3} + \frac{y}{3}$

Substitute the values $a = 2$ , $b = 79$ , and $c = 932$ into the quadratic formula and solve for $y$ .

$\frac{- 79 \pm \sqrt{79^{2} - 4 \cdot (2 \cdot 932)}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Simplify.

Simplify the numerator.

Raise $79$ to the power of $2$ .

$y = \frac{- 79 \pm \sqrt{6241 - 4 \cdot 2 \cdot 932}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $- 4$ by $2$ .

$y = \frac{- 79 \pm \sqrt{6241 - 8 \cdot 932}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $- 8$ by $932$ .

$y = \frac{- 79 \pm \sqrt{6241 - 7456}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Subtract $7456$ from $6241$ .

$y = \frac{- 79 \pm \sqrt{- 1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $- 1215$ as $- 1 (1215)$ .

$y = \frac{- 79 \pm \sqrt{- 1 \cdot 1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $\sqrt{- 1 (1215)}$ as $\sqrt{- 1} \cdot \sqrt{1215}$ .

$y = \frac{- 79 \pm \sqrt{- 1} \cdot \sqrt{1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $\sqrt{- 1}$ as $i$ .

$y = \frac{- 79 \pm i \cdot \sqrt{1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $1215$ as $9^{2} \cdot 15$ .

Factor $81$ out of $1215$ .

$y = \frac{- 79 \pm i \cdot \sqrt{81 (15)}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $81$ as $9^{2}$ .

$y = \frac{- 79 \pm i \cdot \sqrt{9^{2} \cdot 15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = \frac{- 79 \pm i \cdot \sqrt{9^{2} \cdot 15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Pull terms out from under the radical.

$y = \frac{- 79 \pm i \cdot (9 \sqrt{15})}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Move $9$ to the left of $i$ .

$y = \frac{- 79 \pm 9 i \sqrt{15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = \frac{- 79 \pm 9 i \sqrt{15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $2$ by $2$ .

$y = \frac{- 79 \pm 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = \frac{- 79 \pm 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Simplify the expression to solve for the $+$ portion of the $\pm$ .

Simplify the numerator.

Raise $79$ to the power of $2$ .

$y = \frac{- 79 \pm \sqrt{6241 - 4 \cdot 2 \cdot 932}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $- 4$ by $2$ .

$y = \frac{- 79 \pm \sqrt{6241 - 8 \cdot 932}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $- 8$ by $932$ .

$y = \frac{- 79 \pm \sqrt{6241 - 7456}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Subtract $7456$ from $6241$ .

$y = \frac{- 79 \pm \sqrt{- 1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $- 1215$ as $- 1 (1215)$ .

$y = \frac{- 79 \pm \sqrt{- 1 \cdot 1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $\sqrt{- 1 (1215)}$ as $\sqrt{- 1} \cdot \sqrt{1215}$ .

$y = \frac{- 79 \pm \sqrt{- 1} \cdot \sqrt{1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $\sqrt{- 1}$ as $i$ .

$y = \frac{- 79 \pm i \cdot \sqrt{1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $1215$ as $9^{2} \cdot 15$ .

Factor $81$ out of $1215$ .

$y = \frac{- 79 \pm i \cdot \sqrt{81 (15)}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $81$ as $9^{2}$ .

$y = \frac{- 79 \pm i \cdot \sqrt{9^{2} \cdot 15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = \frac{- 79 \pm i \cdot \sqrt{9^{2} \cdot 15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Pull terms out from under the radical.

$y = \frac{- 79 \pm i \cdot (9 \sqrt{15})}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Move $9$ to the left of $i$ .

$y = \frac{- 79 \pm 9 i \sqrt{15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = \frac{- 79 \pm 9 i \sqrt{15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $2$ by $2$ .

$y = \frac{- 79 \pm 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Change the $\pm$ to $+$ .

$y = \frac{- 79 + 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $- 79$ as $- 1 (79)$ .

$y = \frac{- 1 \cdot 79 + 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Factor $- 1$ out of $9 i \sqrt{15}$ .

$y = \frac{- 1 \cdot 79 - (- 9 i \sqrt{15})}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Factor $- 1$ out of $- 1 (79) - (- 9 i \sqrt{15})$ .

$y = \frac{- 1 (79 - 9 i \sqrt{15})}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Move the negative in front of the fraction.

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Simplify the expression to solve for the $-$ portion of the $\pm$ .

Simplify the numerator.

Raise $79$ to the power of $2$ .

$y = \frac{- 79 \pm \sqrt{6241 - 4 \cdot 2 \cdot 932}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $- 4$ by $2$ .

$y = \frac{- 79 \pm \sqrt{6241 - 8 \cdot 932}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $- 8$ by $932$ .

$y = \frac{- 79 \pm \sqrt{6241 - 7456}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Subtract $7456$ from $6241$ .

$y = \frac{- 79 \pm \sqrt{- 1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $- 1215$ as $- 1 (1215)$ .

$y = \frac{- 79 \pm \sqrt{- 1 \cdot 1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $\sqrt{- 1 (1215)}$ as $\sqrt{- 1} \cdot \sqrt{1215}$ .

$y = \frac{- 79 \pm \sqrt{- 1} \cdot \sqrt{1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $\sqrt{- 1}$ as $i$ .

$y = \frac{- 79 \pm i \cdot \sqrt{1215}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $1215$ as $9^{2} \cdot 15$ .

Factor $81$ out of $1215$ .

$y = \frac{- 79 \pm i \cdot \sqrt{81 (15)}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $81$ as $9^{2}$ .

$y = \frac{- 79 \pm i \cdot \sqrt{9^{2} \cdot 15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = \frac{- 79 \pm i \cdot \sqrt{9^{2} \cdot 15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Pull terms out from under the radical.

$y = \frac{- 79 \pm i \cdot (9 \sqrt{15})}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Move $9$ to the left of $i$ .

$y = \frac{- 79 \pm 9 i \sqrt{15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = \frac{- 79 \pm 9 i \sqrt{15}}{2 \cdot 2}$

$x = \frac{7}{3} + \frac{y}{3}$

Multiply $2$ by $2$ .

$y = \frac{- 79 \pm 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Change the $\pm$ to $-$ .

$y = \frac{- 79 - 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Rewrite $- 79$ as $- 1 (79)$ .

$y = \frac{- 1 \cdot 79 - 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Factor $- 1$ out of $- 9 i \sqrt{15}$ .

$y = \frac{- 1 \cdot 79 - (9 i \sqrt{15})}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Factor $- 1$ out of $- 1 (79) - (9 i \sqrt{15})$ .

$y = \frac{- 1 (79 + 9 i \sqrt{15})}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Move the negative in front of the fraction.

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

The final answer is the combination of both solutions.

$y = - \frac{79 - 9 i \sqrt{15}}{4}, - \frac{79 + 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}, - \frac{79 + 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}, - \frac{79 + 9 i \sqrt{15}}{4}$

$x = \frac{7}{3} + \frac{y}{3}$

Replace all occurrences of $y$ with $- \frac{79 - 9 i \sqrt{15}}{4}$ in each equation.

Replace all occurrences of $y$ in $x = \frac{7}{3} + \frac{y}{3}$ with $- \frac{79 - 9 i \sqrt{15}}{4}$ .

$x = \frac{7}{3} + \frac{- \frac{79 - 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Simplify the right side.

Simplify $\frac{7}{3} + \frac{- \frac{79 - 9 i \sqrt{15}}{4}}{3}$ .

Combine the numerators over the common denominator.

$x = \frac{7 - \frac{79 - 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

To write $7$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$x = \frac{7 \cdot \frac{4}{4} - \frac{79 - 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Combine $7$ and $\frac{4}{4}$ .

$x = \frac{\frac{7 \cdot 4}{4} - \frac{79 - 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Combine the numerators over the common denominator.

$x = \frac{\frac{- 51 + 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Rewrite $- 51$ as $- 1 (51)$ .

$x = \frac{\frac{- 1 \cdot 51 + 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Factor $- 1$ out of $9 i \sqrt{15}$ .

$x = \frac{\frac{- 1 \cdot 51 - (- 9 i \sqrt{15})}{4}}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Factor $- 1$ out of $- 1 (51) - (- 9 i \sqrt{15})$ .

$x = \frac{\frac{- 1 (51 - 9 i \sqrt{15})}{4}}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Move the negative in front of the fraction.

$x = \frac{- \frac{51 - 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Multiply the numerator by the reciprocal of the denominator.

$x = - \frac{51 - 9 i \sqrt{15}}{4} \cdot \frac{1}{3}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Multiply $- \frac{51 - 9 i \sqrt{15}}{4} \cdot \frac{1}{3}$ .

Multiply $\frac{1}{3}$ by $\frac{51 - 9 i \sqrt{15}}{4}$ .

$x = - \frac{51 - 9 i \sqrt{15}}{3 \cdot 4}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Multiply $3$ by $4$ .

$x = - \frac{51 - 9 i \sqrt{15}}{12}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

$x = - \frac{51 - 9 i \sqrt{15}}{12}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Cancel the common factor of $51 - 9 i \sqrt{15}$ and $12$ .

Factor $3$ out of $51$ .

$x = - \frac{3 (17) - 9 i \sqrt{15}}{12}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Factor $3$ out of $- 9 i \sqrt{15}$ .

$x = - \frac{3 (17) + 3 (- 3 i \sqrt{15})}{12}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Factor $3$ out of $3 (17) + 3 (- 3 i \sqrt{15})$ .

$x = - \frac{3 (17 - 3 i \sqrt{15})}{12}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Cancel the common factors.

Factor $3$ out of $12$ .

$x = - \frac{3 (17 - 3 i \sqrt{15})}{3 \cdot 4}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Cancel the common factor.

$x = - \frac{3 (17 - 3 i \sqrt{15})}{3 \cdot 4}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Rewrite the expression.

$x = - \frac{17 - 3 i \sqrt{15}}{4}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

$x = - \frac{17 - 3 i \sqrt{15}}{4}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

$x = - \frac{17 - 3 i \sqrt{15}}{4}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

$x = - \frac{17 - 3 i \sqrt{15}}{4}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

$x = - \frac{17 - 3 i \sqrt{15}}{4}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

$x = - \frac{17 - 3 i \sqrt{15}}{4}$

$y = - \frac{79 - 9 i \sqrt{15}}{4}$

Replace all occurrences of $y$ with $- \frac{79 + 9 i \sqrt{15}}{4}$ in each equation.

Replace all occurrences of $y$ in $x = \frac{7}{3} + \frac{y}{3}$ with $- \frac{79 + 9 i \sqrt{15}}{4}$ .

$x = \frac{7}{3} + \frac{- \frac{79 + 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Simplify the right side.

Simplify $\frac{7}{3} + \frac{- \frac{79 + 9 i \sqrt{15}}{4}}{3}$ .

Combine the numerators over the common denominator.

$x = \frac{7 - \frac{79 + 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

To write $7$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$x = \frac{7 \cdot \frac{4}{4} - \frac{79 + 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Combine $7$ and $\frac{4}{4}$ .

$x = \frac{\frac{7 \cdot 4}{4} - \frac{79 + 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Combine the numerators over the common denominator.

$x = \frac{\frac{- 51 - 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Rewrite $- 51$ as $- 1 (51)$ .

$x = \frac{\frac{- 1 \cdot 51 - 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Factor $- 1$ out of $- 9 i \sqrt{15}$ .

$x = \frac{\frac{- 1 \cdot 51 - (9 i \sqrt{15})}{4}}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Factor $- 1$ out of $- 1 (51) - (9 i \sqrt{15})$ .

$x = \frac{\frac{- 1 (51 + 9 i \sqrt{15})}{4}}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Move the negative in front of the fraction.

$x = \frac{- \frac{51 + 9 i \sqrt{15}}{4}}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Multiply the numerator by the reciprocal of the denominator.

$x = - \frac{51 + 9 i \sqrt{15}}{4} \cdot \frac{1}{3}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Multiply $- \frac{51 + 9 i \sqrt{15}}{4} \cdot \frac{1}{3}$ .

Multiply $\frac{1}{3}$ by $\frac{51 + 9 i \sqrt{15}}{4}$ .

$x = - \frac{51 + 9 i \sqrt{15}}{3 \cdot 4}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Multiply $3$ by $4$ .

$x = - \frac{51 + 9 i \sqrt{15}}{12}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

$x = - \frac{51 + 9 i \sqrt{15}}{12}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Cancel the common factor of $51 + 9 i \sqrt{15}$ and $12$ .

Factor $3$ out of $51$ .

$x = - \frac{3 (17) + 9 i \sqrt{15}}{12}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Factor $3$ out of $9 i \sqrt{15}$ .

$x = - \frac{3 (17) + 3 (3 i \sqrt{15})}{12}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Factor $3$ out of $3 (17) + 3 (3 i \sqrt{15})$ .

$x = - \frac{3 (17 + 3 i \sqrt{15})}{12}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Cancel the common factors.

Factor $3$ out of $12$ .

$x = - \frac{3 (17 + 3 i \sqrt{15})}{3 \cdot 4}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Cancel the common factor.

$x = - \frac{3 (17 + 3 i \sqrt{15})}{3 \cdot 4}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

Rewrite the expression.

$x = - \frac{17 + 3 i \sqrt{15}}{4}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

$x = - \frac{17 + 3 i \sqrt{15}}{4}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

$x = - \frac{17 + 3 i \sqrt{15}}{4}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

$x = - \frac{17 + 3 i \sqrt{15}}{4}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

$x = - \frac{17 + 3 i \sqrt{15}}{4}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

$x = - \frac{17 + 3 i \sqrt{15}}{4}$

$y = - \frac{79 + 9 i \sqrt{15}}{4}$

List all of the solutions.

$x = - \frac{17 - 3 i \sqrt{15}}{4}, y = - \frac{79 - 9 i \sqrt{15}}{4}$

$x = - \frac{17 + 3 i \sqrt{15}}{4}, y = - \frac{79 + 9 i \sqrt{15}}{4}$

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