Solve the System of Equations 5/4x+9/10y=2/5 -5/7x+5/9y=130/21

$\frac{5}{4} x + \frac{9}{10} y = \frac{2}{5}$ $- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Solve for $x$ in $\frac{5}{4} x + \frac{9}{10} y = \frac{2}{5}$ .

Simplify each term.

Combine $\frac{5}{4}$ and $x$ .

$\frac{5 x}{4} + \frac{9}{10} y = \frac{2}{5}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Combine $\frac{9}{10}$ and $y$ .

$\frac{5 x}{4} + \frac{9 y}{10} = \frac{2}{5}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$\frac{5 x}{4} + \frac{9 y}{10} = \frac{2}{5}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Subtract $\frac{9 y}{10}$ from both sides of the equation.

$\frac{5 x}{4} = \frac{2}{5} - \frac{9 y}{10}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Multiply both sides of the equation by $\frac{4}{5}$ .

$\frac{4}{5} \cdot \frac{5 x}{4} = \frac{4}{5} \cdot (\frac{2}{5} - \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{4}{5} \cdot \frac{5 x}{4}$ .

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4}{5} \cdot \frac{5 x}{4} = \frac{4}{5} \cdot (\frac{2}{5} - \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Rewrite the expression.

$\frac{1}{5} \cdot (5 x) = \frac{4}{5} \cdot (\frac{2}{5} - \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$\frac{1}{5} \cdot (5 x) = \frac{4}{5} \cdot (\frac{2}{5} - \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Cancel the common factor of $5$ .

Factor $5$ out of $5 x$ .

$\frac{1}{5} \cdot (5 (x)) = \frac{4}{5} \cdot (\frac{2}{5} - \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Cancel the common factor.

$\frac{1}{5} \cdot (5 x) = \frac{4}{5} \cdot (\frac{2}{5} - \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Rewrite the expression.

$x = \frac{4}{5} \cdot (\frac{2}{5} - \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = \frac{4}{5} \cdot (\frac{2}{5} - \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = \frac{4}{5} \cdot (\frac{2}{5} - \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = \frac{4}{5} \cdot (\frac{2}{5} - \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Simplify the right side.

Simplify $\frac{4}{5} (\frac{2}{5} - \frac{9 y}{10})$ .

Apply the distributive property.

$x = \frac{4}{5} \cdot \frac{2}{5} + \frac{4}{5} \cdot (- \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Multiply $\frac{4}{5} \cdot \frac{2}{5}$ .

Multiply $\frac{4}{5}$ by $\frac{2}{5}$ .

$x = \frac{4 \cdot 2}{5 \cdot 5} + \frac{4}{5} \cdot (- \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Multiply $4$ by $2$ .

$x = \frac{8}{5 \cdot 5} + \frac{4}{5} \cdot (- \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Multiply $5$ by $5$ .

$x = \frac{8}{25} + \frac{4}{5} \cdot (- \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = \frac{8}{25} + \frac{4}{5} \cdot (- \frac{9 y}{10})$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Simplify terms.

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{9 y}{10}$ into the numerator.

$x = \frac{8}{25} + \frac{4}{5} \cdot \frac{- 9 y}{10}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Factor $2$ out of $4$ .

$x = \frac{8}{25} + \frac{2 (2)}{5} \cdot \frac{- 9 y}{10}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Factor $2$ out of $10$ .

$x = \frac{8}{25} + \frac{2 \cdot 2}{5} \cdot \frac{- 9 y}{2 \cdot 5}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Cancel the common factor.

$x = \frac{8}{25} + \frac{2 \cdot 2}{5} \cdot \frac{- 9 y}{2 \cdot 5}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Rewrite the expression.

$x = \frac{8}{25} + \frac{2}{5} \cdot \frac{- 9 y}{5}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = \frac{8}{25} + \frac{2}{5} \cdot \frac{- 9 y}{5}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Multiply $\frac{2}{5}$ by $\frac{- 9 y}{5}$ .

$x = \frac{8}{25} + \frac{2 (- 9 y)}{5 \cdot 5}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Multiply.

Multiply $- 9$ by $2$ .

$x = \frac{8}{25} + \frac{- 18 y}{5 \cdot 5}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Multiply $5$ by $5$ .

$x = \frac{8}{25} + \frac{- 18 y}{25}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = \frac{8}{25} + \frac{- 18 y}{25}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = \frac{8}{25} + \frac{- 18 y}{25}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Move the negative in front of the fraction.

$x = \frac{8}{25} - \frac{18 y}{25}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = \frac{8}{25} - \frac{18 y}{25}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = \frac{8}{25} - \frac{18 y}{25}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = \frac{8}{25} - \frac{18 y}{25}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Reorder $\frac{8}{25}$ and $- \frac{18 y}{25}$ .

$x = - \frac{18 y}{25} + \frac{8}{25}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$

Replace all occurrences of $x$ with $- \frac{18 y}{25} + \frac{8}{25}$ in each equation.

Replace all occurrences of $x$ in $- \frac{5}{7} x + \frac{5}{9} y = \frac{130}{21}$ with $- \frac{18 y}{25} + \frac{8}{25}$ .

$- \frac{5}{7} \cdot (- \frac{18 y}{25} + \frac{8}{25}) + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Simplify the left side.

Simplify $- \frac{5}{7} \cdot (- \frac{18 y}{25} + \frac{8}{25}) + \frac{5}{9} y$ .

Simplify each term.

Apply the distributive property.

$- \frac{5}{7} \cdot (- \frac{18 y}{25}) - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{5}{7}$ into the numerator.

$\frac{- 5}{7} \cdot (- \frac{18 y}{25}) - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Move the leading negative in $- \frac{18 y}{25}$ into the numerator.

$\frac{- 5}{7} \cdot \frac{- 18 y}{25} - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Factor $5$ out of $- 5$ .

$\frac{5 (- 1)}{7} \cdot \frac{- 18 y}{25} - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Factor $5$ out of $25$ .

$\frac{5 \cdot - 1}{7} \cdot \frac{- 18 y}{5 \cdot 5} - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Cancel the common factor.

$\frac{5 \cdot - 1}{7} \cdot \frac{- 18 y}{5 \cdot 5} - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Rewrite the expression.

$\frac{- 1}{7} \cdot \frac{- 18 y}{5} - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{- 1}{7} \cdot \frac{- 18 y}{5} - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $\frac{- 1}{7}$ by $\frac{- 18 y}{5}$ .

$\frac{- (- 18 y)}{7 \cdot 5} - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $- 18$ by $- 1$ .

$\frac{18 y}{7 \cdot 5} - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $7$ by $5$ .

$\frac{18 y}{35} - \frac{5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{5}{7}$ into the numerator.

$\frac{18 y}{35} + \frac{- 5}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Factor $5$ out of $- 5$ .

$\frac{18 y}{35} + \frac{5 (- 1)}{7} \cdot \frac{8}{25} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Factor $5$ out of $25$ .

$\frac{18 y}{35} + \frac{5 \cdot - 1}{7} \cdot \frac{8}{5 \cdot 5} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Cancel the common factor.

$\frac{18 y}{35} + \frac{5 \cdot - 1}{7} \cdot \frac{8}{5 \cdot 5} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Rewrite the expression.

$\frac{18 y}{35} + \frac{- 1}{7} \cdot \frac{8}{5} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{18 y}{35} + \frac{- 1}{7} \cdot \frac{8}{5} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $\frac{- 1}{7}$ by $\frac{8}{5}$ .

$\frac{18 y}{35} + \frac{- 1 \cdot 8}{7 \cdot 5} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $- 1$ by $8$ .

$\frac{18 y}{35} + \frac{- 8}{7 \cdot 5} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $7$ by $5$ .

$\frac{18 y}{35} + \frac{- 8}{35} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Move the negative in front of the fraction.

$\frac{18 y}{35} - \frac{8}{35} + \frac{5}{9} y = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Combine $\frac{5}{9}$ and $y$ .

$\frac{18 y}{35} - \frac{8}{35} + \frac{5 y}{9} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{18 y}{35} - \frac{8}{35} + \frac{5 y}{9} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

To write $\frac{18 y}{35}$ as a fraction with a common denominator, multiply by $\frac{9}{9}$ .

$\frac{18 y}{35} \cdot \frac{9}{9} + \frac{5 y}{9} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

To write $\frac{5 y}{9}$ as a fraction with a common denominator, multiply by $\frac{35}{35}$ .

$\frac{18 y}{35} \cdot \frac{9}{9} + \frac{5 y}{9} \cdot \frac{35}{35} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Write each expression with a common denominator of $315$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{18 y}{35}$ by $\frac{9}{9}$ .

$\frac{18 y \cdot 9}{35 \cdot 9} + \frac{5 y}{9} \cdot \frac{35}{35} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $35$ by $9$ .

$\frac{18 y \cdot 9}{315} + \frac{5 y}{9} \cdot \frac{35}{35} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $\frac{5 y}{9}$ by $\frac{35}{35}$ .

$\frac{18 y \cdot 9}{315} + \frac{5 y \cdot 35}{9 \cdot 35} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $9$ by $35$ .

$\frac{18 y \cdot 9}{315} + \frac{5 y \cdot 35}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{18 y \cdot 9}{315} + \frac{5 y \cdot 35}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Combine the numerators over the common denominator.

$\frac{18 y \cdot 9 + 5 y \cdot 35}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Simplify each term.

Simplify the numerator.

Factor $y$ out of $18 y \cdot 9 + 5 y \cdot 35$ .

Factor $y$ out of $18 y \cdot 9$ .

$\frac{y (18 \cdot 9) + 5 y \cdot 35}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Factor $y$ out of $5 y \cdot 35$ .

$\frac{y (18 \cdot 9) + y (5 \cdot 35)}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Factor $y$ out of $y (18 \cdot 9) + y (5 \cdot 35)$ .

$\frac{y (18 \cdot 9 + 5 \cdot 35)}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{y (18 \cdot 9 + 5 \cdot 35)}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $18$ by $9$ .

$\frac{y (162 + 5 \cdot 35)}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $5$ by $35$ .

$\frac{y (162 + 175)}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Add $162$ and $175$ .

$\frac{y \cdot 337}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{y \cdot 337}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Move $337$ to the left of $y$ .

$\frac{337 y}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{337 y}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{337 y}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{337 y}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{337 y}{315} - \frac{8}{35} = \frac{130}{21}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Solve for $y$ in $\frac{337 y}{315} - \frac{8}{35} = \frac{130}{21}$ .

Move all terms not containing $y$ to the right side of the equation.

Add $\frac{8}{35}$ to both sides of the equation.

$\frac{337 y}{315} = \frac{130}{21} + \frac{8}{35}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

To write $\frac{130}{21}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$\frac{337 y}{315} = \frac{130}{21} \cdot \frac{5}{5} + \frac{8}{35}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

To write $\frac{8}{35}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{337 y}{315} = \frac{130}{21} \cdot \frac{5}{5} + \frac{8}{35} \cdot \frac{3}{3}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Write each expression with a common denominator of $105$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{130}{21}$ by $\frac{5}{5}$ .

$\frac{337 y}{315} = \frac{130 \cdot 5}{21 \cdot 5} + \frac{8}{35} \cdot \frac{3}{3}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $21$ by $5$ .

$\frac{337 y}{315} = \frac{130 \cdot 5}{105} + \frac{8}{35} \cdot \frac{3}{3}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $\frac{8}{35}$ by $\frac{3}{3}$ .

$\frac{337 y}{315} = \frac{130 \cdot 5}{105} + \frac{8 \cdot 3}{35 \cdot 3}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $35$ by $3$ .

$\frac{337 y}{315} = \frac{130 \cdot 5}{105} + \frac{8 \cdot 3}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{337 y}{315} = \frac{130 \cdot 5}{105} + \frac{8 \cdot 3}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Combine the numerators over the common denominator.

$\frac{337 y}{315} = \frac{130 \cdot 5 + 8 \cdot 3}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Simplify the numerator.

Multiply $130$ by $5$ .

$\frac{337 y}{315} = \frac{650 + 8 \cdot 3}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $8$ by $3$ .

$\frac{337 y}{315} = \frac{650 + 24}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Add $650$ and $24$ .

$\frac{337 y}{315} = \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{337 y}{315} = \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{337 y}{315} = \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply both sides of the equation by $\frac{315}{337}$ .

$\frac{315}{337} \cdot \frac{337 y}{315} = \frac{315}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{315}{337} \cdot \frac{337 y}{315}$ .

Cancel the common factor of $315$ .

Cancel the common factor.

$\frac{315}{337} \cdot \frac{337 y}{315} = \frac{315}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Rewrite the expression.

$\frac{1}{337} \cdot (337 y) = \frac{315}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$\frac{1}{337} \cdot (337 y) = \frac{315}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Cancel the common factor of $337$ .

Factor $337$ out of $337 y$ .

$\frac{1}{337} \cdot (337 (y)) = \frac{315}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Cancel the common factor.

$\frac{1}{337} \cdot (337 y) = \frac{315}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Rewrite the expression.

$y = \frac{315}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$y = \frac{315}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$y = \frac{315}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$y = \frac{315}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Simplify the right side.

Simplify $\frac{315}{337} \cdot \frac{674}{105}$ .

Cancel the common factor of $105$ .

Factor $105$ out of $315$ .

$y = \frac{105 (3)}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Cancel the common factor.

$y = \frac{105 \cdot 3}{337} \cdot \frac{674}{105}$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Rewrite the expression.

$y = \frac{3}{337} \cdot 674$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$y = \frac{3}{337} \cdot 674$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Cancel the common factor of $337$ .

Factor $337$ out of $674$ .

$y = \frac{3}{337} \cdot (337 (2))$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Cancel the common factor.

$y = \frac{3}{337} \cdot (337 \cdot 2)$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Rewrite the expression.

$y = 3 \cdot 2$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$y = 3 \cdot 2$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Multiply $3$ by $2$ .

$y = 6$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$y = 6$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$y = 6$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$y = 6$

$x = - \frac{18 y}{25} + \frac{8}{25}$

$y = 6$

$x = - \frac{18 y}{25} + \frac{8}{25}$

Replace all occurrences of $y$ with $6$ in each equation.

Replace all occurrences of $y$ in $x = - \frac{18 y}{25} + \frac{8}{25}$ with $6$ .

$x = - \frac{18 (6)}{25} + \frac{8}{25}$

$y = 6$

Simplify the right side.

Simplify $- \frac{18 (6)}{25} + \frac{8}{25}$ .

Combine the numerators over the common denominator.

$x = \frac{- 18 \cdot 6 + 8}{25}$

$y = 6$

Simplify the expression.

Multiply $- 18$ by $6$ .

$x = \frac{- 108 + 8}{25}$

$y = 6$

Add $- 108$ and $8$ .

$x = \frac{- 100}{25}$

$y = 6$

Divide $- 100$ by $25$ .

$x = - 4$

$y = 6$

$x = - 4$

$y = 6$

$x = - 4$

$y = 6$

$x = - 4$

$y = 6$

$x = - 4$

$y = 6$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 4, 6)$

The result can be shown in multiple forms.

Point Form:

$(- 4, 6)$

Equation Form:

$x = - 4, y = 6$

Solve the System of Equations 5/4x+9/10y=2/5 -5/7x+5/9y=130/21

Related Questions

Support LCMGCF.com by disabling your adblocker.