Solve the System of Equations 9x^2+25y^2=225 10y+6x=6

$9 x^{2} + 25 y^{2} = 225$ $10 y + 6 x = 6$

Solve for $y$ in $10 y + 6 x = 6$ .

Subtract $6 x$ from both sides of the equation.

$10 y = 6 - 6 x$

$9 x^{2} + 25 y^{2} = 225$

Divide each term in $10 y = 6 - 6 x$ by $10$ and simplify.

Divide each term in $10 y = 6 - 6 x$ by $10$ .

$\frac{10 y}{10} = \frac{6}{10} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 y}{10} = \frac{6}{10} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

Divide $y$ by $1$ .

$y = \frac{6}{10} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

$y = \frac{6}{10} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

$y = \frac{6}{10} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

Simplify the right side.

Simplify each term.

Cancel the common factor of $6$ and $10$ .

Factor $2$ out of $6$ .

$y = \frac{2 (3)}{10} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

Cancel the common factors.

Factor $2$ out of $10$ .

$y = \frac{2 \cdot 3}{2 \cdot 5} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

Cancel the common factor.

$y = \frac{2 \cdot 3}{2 \cdot 5} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

Rewrite the expression.

$y = \frac{3}{5} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

$y = \frac{3}{5} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

$y = \frac{3}{5} + \frac{- 6 x}{10}$

$9 x^{2} + 25 y^{2} = 225$

Cancel the common factor of $- 6$ and $10$ .

Factor $2$ out of $- 6 x$ .

$y = \frac{3}{5} + \frac{2 (- 3 x)}{10}$

$9 x^{2} + 25 y^{2} = 225$

Cancel the common factors.

Factor $2$ out of $10$ .

$y = \frac{3}{5} + \frac{2 (- 3 x)}{2 (5)}$

$9 x^{2} + 25 y^{2} = 225$

Cancel the common factor.

$y = \frac{3}{5} + \frac{2 (- 3 x)}{2 \cdot 5}$

$9 x^{2} + 25 y^{2} = 225$

Rewrite the expression.

$y = \frac{3}{5} + \frac{- 3 x}{5}$

$9 x^{2} + 25 y^{2} = 225$

$y = \frac{3}{5} + \frac{- 3 x}{5}$

$9 x^{2} + 25 y^{2} = 225$

$y = \frac{3}{5} + \frac{- 3 x}{5}$

$9 x^{2} + 25 y^{2} = 225$

Move the negative in front of the fraction.

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 y^{2} = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 y^{2} = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 y^{2} = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 y^{2} = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 y^{2} = 225$

Replace all occurrences of $y$ with $\frac{3}{5} - \frac{3 x}{5}$ in each equation.

Replace all occurrences of $y$ in $9 x^{2} + 25 y^{2} = 225$ with $\frac{3}{5} - \frac{3 x}{5}$ .

$9 x^{2} + 25 {(\frac{3}{5} - \frac{3 x}{5})}^{2} = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Simplify the left side.

Simplify $9 x^{2} + 25 {(\frac{3}{5} - \frac{3 x}{5})}^{2}$ .

Simplify each term.

Rewrite ${(\frac{3}{5} - \frac{3 x}{5})}^{2}$ as $(\frac{3}{5} - \frac{3 x}{5}) (\frac{3}{5} - \frac{3 x}{5})$ .

$9 x^{2} + 25 ((\frac{3}{5} - \frac{3 x}{5}) (\frac{3}{5} - \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Expand $(\frac{3}{5} - \frac{3 x}{5}) (\frac{3}{5} - \frac{3 x}{5})$ using the FOIL Method.

Apply the distributive property.

$9 x^{2} + 25 (\frac{3}{5} \cdot (\frac{3}{5} - \frac{3 x}{5}) - \frac{3 x}{5} \cdot (\frac{3}{5} - \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Apply the distributive property.

$9 x^{2} + 25 (\frac{3}{5} \cdot \frac{3}{5} + \frac{3}{5} \cdot (- \frac{3 x}{5}) - \frac{3 x}{5} \cdot (\frac{3}{5} - \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Apply the distributive property.

$9 x^{2} + 25 (\frac{3}{5} \cdot \frac{3}{5} + \frac{3}{5} \cdot (- \frac{3 x}{5}) - \frac{3 x}{5} \cdot \frac{3}{5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 (\frac{3}{5} \cdot \frac{3}{5} + \frac{3}{5} \cdot (- \frac{3 x}{5}) - \frac{3 x}{5} \cdot \frac{3}{5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Simplify and combine like terms.

Simplify each term.

Multiply $\frac{3}{5} \cdot \frac{3}{5}$ .

Multiply $\frac{3}{5}$ by $\frac{3}{5}$ .

$9 x^{2} + 25 (\frac{3 \cdot 3}{5 \cdot 5} + \frac{3}{5} \cdot (- \frac{3 x}{5}) - \frac{3 x}{5} \cdot \frac{3}{5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $3$ by $3$ .

$9 x^{2} + 25 (\frac{9}{5 \cdot 5} + \frac{3}{5} \cdot (- \frac{3 x}{5}) - \frac{3 x}{5} \cdot \frac{3}{5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $5$ by $5$ .

$9 x^{2} + 25 (\frac{9}{25} + \frac{3}{5} \cdot (- \frac{3 x}{5}) - \frac{3 x}{5} \cdot \frac{3}{5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 (\frac{9}{25} + \frac{3}{5} \cdot (- \frac{3 x}{5}) - \frac{3 x}{5} \cdot \frac{3}{5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $\frac{3}{5} (- \frac{3 x}{5})$ .

Multiply $\frac{3}{5}$ by $\frac{3 x}{5}$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{3 (3 x)}{5 \cdot 5} - \frac{3 x}{5} \cdot \frac{3}{5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $3$ by $3$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{5 \cdot 5} - \frac{3 x}{5} \cdot \frac{3}{5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $5$ by $5$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{3 x}{5} \cdot \frac{3}{5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{3 x}{5} \cdot \frac{3}{5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $- \frac{3 x}{5} \cdot \frac{3}{5}$ .

Multiply $\frac{3}{5}$ by $\frac{3 x}{5}$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{3 (3 x)}{5 \cdot 5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $3$ by $3$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{5 \cdot 5} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $5$ by $5$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} - \frac{3 x}{5} \cdot (- \frac{3 x}{5})) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $- \frac{3 x}{5} (- \frac{3 x}{5})$ .

Multiply $- 1$ by $- 1$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + 1 (\frac{3 x}{5}) \cdot \frac{3 x}{5}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $\frac{3 x}{5}$ by $1$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + \frac{3 x}{5} \cdot \frac{3 x}{5}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $\frac{3 x}{5}$ by $\frac{3 x}{5}$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + \frac{3 x (3 x)}{5 \cdot 5}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $3$ by $3$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + \frac{9 x \cdot x}{5 \cdot 5}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Raise $x$ to the power of $1$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + \frac{9 (x \cdot x)}{5 \cdot 5}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Raise $x$ to the power of $1$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + \frac{9 (x \cdot x)}{5 \cdot 5}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + \frac{9 x^{1 + 1}}{5 \cdot 5}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Add $1$ and $1$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + \frac{9 x^{2}}{5 \cdot 5}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $5$ by $5$ .

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + \frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + \frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 (\frac{9}{25} - \frac{9 x}{25} - \frac{9 x}{25} + \frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Subtract $\frac{9 x}{25}$ from $- \frac{9 x}{25}$ .

$9 x^{2} + 25 (\frac{9}{25} - 2 \frac{9 x}{25} + \frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 (\frac{9}{25} - 2 \frac{9 x}{25} + \frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Simplify each term.

Multiply $- 2 \frac{9 x}{25}$ .

Combine $- 2$ and $\frac{9 x}{25}$ .

$9 x^{2} + 25 (\frac{9}{25} + \frac{- 2 (9 x)}{25} + \frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Multiply $9$ by $- 2$ .

$9 x^{2} + 25 (\frac{9}{25} + \frac{- 18 x}{25} + \frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 (\frac{9}{25} + \frac{- 18 x}{25} + \frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Move the negative in front of the fraction.

$9 x^{2} + 25 (\frac{9}{25} - \frac{18 x}{25} + \frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 25 (\frac{9}{25} - \frac{18 x}{25} + \frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Apply the distributive property.

$9 x^{2} + 25 (\frac{9}{25}) + 25 (- \frac{18 x}{25}) + 25 (\frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Simplify.

Cancel the common factor of $25$ .

Cancel the common factor.

$9 x^{2} + 25 (\frac{9}{25}) + 25 (- \frac{18 x}{25}) + 25 (\frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Rewrite the expression.

$9 x^{2} + 9 + 25 (- \frac{18 x}{25}) + 25 (\frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 9 + 25 (- \frac{18 x}{25}) + 25 (\frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Cancel the common factor of $25$ .

Move the leading negative in $- \frac{18 x}{25}$ into the numerator.

$9 x^{2} + 9 + 25 (\frac{- 18 x}{25}) + 25 (\frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Cancel the common factor.

$9 x^{2} + 9 + 25 (\frac{- 18 x}{25}) + 25 (\frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Rewrite the expression.

$9 x^{2} + 9 - 18 x + 25 (\frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 9 - 18 x + 25 (\frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Cancel the common factor of $25$ .

Cancel the common factor.

$9 x^{2} + 9 - 18 x + 25 (\frac{9 x^{2}}{25}) = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Rewrite the expression.

$9 x^{2} + 9 - 18 x + 9 x^{2} = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 9 - 18 x + 9 x^{2} = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 9 - 18 x + 9 x^{2} = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$9 x^{2} + 9 - 18 x + 9 x^{2} = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Add $9 x^{2}$ and $9 x^{2}$ .

$18 x^{2} + 9 - 18 x = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$18 x^{2} + 9 - 18 x = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$18 x^{2} + 9 - 18 x = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

$18 x^{2} + 9 - 18 x = 225$

$y = \frac{3}{5} - \frac{3 x}{5}$

Solve for $x$ in $18 x^{2} + 9 - 18 x = 225$ .

Subtract $225$ from both sides of the equation.

$18 x^{2} + 9 - 18 x - 225 = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Subtract $225$ from $9$ .

$18 x^{2} - 18 x - 216 = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Factor the left side of the equation.

Factor $18$ out of $18 x^{2} - 18 x - 216$ .

Factor $18$ out of $18 x^{2}$ .

$18 (x^{2}) - 18 x - 216 = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Factor $18$ out of $- 18 x$ .

$18 (x^{2}) + 18 (- x) - 216 = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Factor $18$ out of $- 216$ .

$18 (x^{2}) + 18 (- x) + 18 (- 12) = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Factor $18$ out of $18 (x^{2}) + 18 (- x)$ .

$18 (x^{2} - x) + 18 (- 12) = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Factor $18$ out of $18 (x^{2} - x) + 18 (- 12)$ .

$18 (x^{2} - x - 12) = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

$18 (x^{2} - x - 12) = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Factor.

Factor $x^{2} - x - 12$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 12$ and whose sum is $- 1$ .

$- 4, 3$

$y = \frac{3}{5} - \frac{3 x}{5}$

Write the factored form using these integers.

$18 ((x - 4) (x + 3)) = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

$18 ((x - 4) (x + 3)) = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Remove unnecessary parentheses.

$18 (x - 4) (x + 3) = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

$18 (x - 4) (x + 3) = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

$18 (x - 4) (x + 3) = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x - 4 = 0$

$x + 3 = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Set $x - 4$ equal to $0$ and solve for $x$ .

Set $x - 4$ equal to $0$ .

$x - 4 = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Add $4$ to both sides of the equation.

$x = 4$

$y = \frac{3}{5} - \frac{3 x}{5}$

$x = 4$

$y = \frac{3}{5} - \frac{3 x}{5}$

Set $x + 3$ equal to $0$ and solve for $x$ .

Set $x + 3$ equal to $0$ .

$x + 3 = 0$

$y = \frac{3}{5} - \frac{3 x}{5}$

Subtract $3$ from both sides of the equation.

$x = - 3$

$y = \frac{3}{5} - \frac{3 x}{5}$

$x = - 3$

$y = \frac{3}{5} - \frac{3 x}{5}$

The final solution is all the values that make $18 (x - 4) (x + 3) = 0$ true.

$x = 4, - 3$

$y = \frac{3}{5} - \frac{3 x}{5}$

$x = 4, - 3$

$y = \frac{3}{5} - \frac{3 x}{5}$

Replace all occurrences of $x$ with $4$ in each equation.

Replace all occurrences of $x$ in $y = \frac{3}{5} - \frac{3 x}{5}$ with $4$ .

$y = \frac{3}{5} - \frac{3 (4)}{5}$

$x = 4$

Simplify the right side.

Simplify $\frac{3}{5} - \frac{3 (4)}{5}$ .

Combine the numerators over the common denominator.

$y = \frac{3 - 3 \cdot 4}{5}$

$x = 4$

Simplify the expression.

Multiply $- 3$ by $4$ .

$y = \frac{3 - 12}{5}$

$x = 4$

Subtract $12$ from $3$ .

$y = \frac{- 9}{5}$

$x = 4$

Move the negative in front of the fraction.

$y = - \frac{9}{5}$

$x = 4$

$y = - \frac{9}{5}$

$x = 4$

$y = - \frac{9}{5}$

$x = 4$

$y = - \frac{9}{5}$

$x = 4$

$y = - \frac{9}{5}$

$x = 4$

Replace all occurrences of $x$ with $- 3$ in each equation.

Replace all occurrences of $x$ in $y = \frac{3}{5} - \frac{3 x}{5}$ with $- 3$ .

$y = \frac{3}{5} - \frac{3 (- 3)}{5}$

$x = - 3$

Simplify the right side.

Simplify $\frac{3}{5} - \frac{3 (- 3)}{5}$ .

Combine the numerators over the common denominator.

$y = \frac{3 - 3 \cdot - 3}{5}$

$x = - 3$

Simplify the expression.

Multiply $- 3$ by $- 3$ .

$y = \frac{3 + 9}{5}$

$x = - 3$

Add $3$ and $9$ .

$y = \frac{12}{5}$

$x = - 3$

$y = \frac{12}{5}$

$x = - 3$

$y = \frac{12}{5}$

$x = - 3$

$y = \frac{12}{5}$

$x = - 3$

$y = \frac{12}{5}$

$x = - 3$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(4, - \frac{9}{5})$

$(- 3, \frac{12}{5})$

The result can be shown in multiple forms.

Point Form:

$(4, - \frac{9}{5}), (- 3, \frac{12}{5})$

Equation Form:

$x = 4, y = - \frac{9}{5}$

$x = - 3, y = \frac{12}{5}$

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