Solve the System of Equations h-z=3 -3h+3z=6

$h - z = 3$ $- 3 h + 3 z = 6$

Step 1

Add $z$ to both sides of the equation.

$h = 3 + z$

$- 3 h + 3 z = 6$

Step 2

Replace all occurrences of $h$ with $3 + z$ in each equation.

Replace all occurrences of $h$ in $- 3 h + 3 z = 6$ with $3 + z$ .

$- 3 (3 + z) + 3 z = 6$

$h = 3 + z$

Simplify the left side.

Simplify $- 3 (3 + z) + 3 z$ .

Simplify each term.

Apply the distributive property.

$- 3 \cdot 3 - 3 z + 3 z = 6$

$h = 3 + z$

Multiply $- 3$ by $3$ .

$- 9 - 3 z + 3 z = 6$

$h = 3 + z$

$- 9 - 3 z + 3 z = 6$

$h = 3 + z$

Combine the opposite terms in $- 9 - 3 z + 3 z$ .

Add $- 3 z$ and $3 z$ .

$- 9 + 0 = 6$

$h = 3 + z$

Add $- 9$ and $0$ .

$- 9 = 6$

$h = 3 + z$

$- 9 = 6$

$h = 3 + z$

$- 9 = 6$

$h = 3 + z$

$- 9 = 6$

$h = 3 + z$

$- 9 = 6$

$h = 3 + z$

Step 3

Since $- 9 = 6$ is not true, there is no solution.

No solution

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