Solve the System of Equations t=-2 x=t^2-2 y=-t+2

$t = - 2$ $x = t^{2} - 2$ $y = - t + 2$

Step 1

Replace all occurrences of $t$ with $- 2$ in each equation.

Replace all occurrences of $t$ in $x = t^{2} - 2$ with $- 2$ .

$x = {(- 2)}^{2} - 2$

$t = - 2$

$y = - t + 2$

Simplify the right side.

Simplify ${(- 2)}^{2} - 2$ .

Raise $- 2$ to the power of $2$ .

$x = 4 - 2$

$t = - 2$

$y = - t + 2$

Subtract $2$ from $4$ .

$x = 2$

$t = - 2$

$y = - t + 2$

$x = 2$

$t = - 2$

$y = - t + 2$

$x = 2$

$t = - 2$

$y = - t + 2$

Replace all occurrences of $t$ in $y = - t + 2$ with $- 2$ .

$y = - (- 2) + 2$

$x = 2$

$t = - 2$

Simplify the right side.

Simplify $- (- 2) + 2$ .

Multiply $- 1$ by $- 2$ .

$y = 2 + 2$

$x = 2$

$t = - 2$

Add $2$ and $2$ .

$y = 4$

$x = 2$

$t = - 2$

$y = 4$

$x = 2$

$t = - 2$

$y = 4$

$x = 2$

$t = - 2$

$y = 4$

$x = 2$

$t = - 2$

Step 2

List all of the solutions.

$y = 4, x = 2, t = - 2$

Solve the System of Equations t=-2 x=t^2-2 y=-t+2

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