Solve the System of Equations x=2(1+2y)-9z y=2(2z-x)-13 z=2(y+4)+3x

$x = 2 (1 + 2 y) - 9 z$ $y = 2 (2 z - x) - 13$ $z = 2 (y + 4) + 3 x$

Step 1

Simplify $2 (1 + 2 y) - 9 z$ .

Simplify each term.

Apply the distributive property.

$x = 2 \cdot 1 + 2 (2 y) - 9 z$

$y = 2 (2 z - x) - 13$

$z = 2 (y + 4) + 3 x$

Multiply $2$ by $1$ .

$x = 2 + 2 (2 y) - 9 z$

$y = 2 (2 z - x) - 13$

$z = 2 (y + 4) + 3 x$

Multiply $2$ by $2$ .

$x = 2 + 4 y - 9 z$

$y = 2 (2 z - x) - 13$

$z = 2 (y + 4) + 3 x$

$x = 2 + 4 y - 9 z$

$y = 2 (2 z - x) - 13$

$z = 2 (y + 4) + 3 x$

Move $2$ .

$x = 4 y - 9 z + 2$

$y = 2 (2 z - x) - 13$

$z = 2 (y + 4) + 3 x$

$x = 4 y - 9 z + 2$

$y = 2 (2 z - x) - 13$

$z = 2 (y + 4) + 3 x$

Step 2

Replace all occurrences of $x$ with $4 y - 9 z + 2$ in each equation.

Replace all occurrences of $x$ in $y = 2 (2 z - x) - 13$ with $4 y - 9 z + 2$ .

$y = 2 (2 z - (4 y - 9 z + 2)) - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Simplify the right side.

Simplify $2 (2 z - (4 y - 9 z + 2)) - 13$ .

Simplify each term.

Apply the distributive property.

$y = 2 (2 z - (4 y) - (- 9 z) - 1 \cdot 2) - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Simplify.

Multiply $4$ by $- 1$ .

$y = 2 (2 z - 4 y - (- 9 z) - 1 \cdot 2) - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Multiply $- 9$ by $- 1$ .

$y = 2 (2 z - 4 y + 9 z - 1 \cdot 2) - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Multiply $- 1$ by $2$ .

$y = 2 (2 z - 4 y + 9 z - 2) - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

$y = 2 (2 z - 4 y + 9 z - 2) - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

$y = 2 (2 z - 4 y + 9 z - 2) - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Add $2 z$ and $9 z$ .

$y = 2 (- 4 y + 11 z - 2) - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Apply the distributive property.

$y = 2 (- 4 y) + 2 (11 z) + 2 \cdot - 2 - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Simplify.

Multiply $- 4$ by $2$ .

$y = - 8 y + 2 (11 z) + 2 \cdot - 2 - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Multiply $11$ by $2$ .

$y = - 8 y + 22 z + 2 \cdot - 2 - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Multiply $2$ by $- 2$ .

$y = - 8 y + 22 z - 4 - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

$y = - 8 y + 22 z - 4 - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

$y = - 8 y + 22 z - 4 - 13$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Subtract $13$ from $- 4$ .

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = 2 (y + 4) + 3 x$

Replace all occurrences of $x$ in $z = 2 (y + 4) + 3 x$ with $4 y - 9 z + 2$ .

$z = 2 (y + 4) + 3 (4 y - 9 z + 2)$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Simplify the right side.

Simplify $2 (y + 4) + 3 (4 y - 9 z + 2)$ .

Simplify each term.

Apply the distributive property.

$z = 2 y + 2 \cdot 4 + 3 (4 y - 9 z + 2)$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Multiply $2$ by $4$ .

$z = 2 y + 8 + 3 (4 y - 9 z + 2)$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Apply the distributive property.

$z = 2 y + 8 + 3 (4 y) + 3 (- 9 z) + 3 \cdot 2$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Simplify.

Multiply $4$ by $3$ .

$z = 2 y + 8 + 12 y + 3 (- 9 z) + 3 \cdot 2$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Multiply $- 9$ by $3$ .

$z = 2 y + 8 + 12 y - 27 z + 3 \cdot 2$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Multiply $3$ by $2$ .

$z = 2 y + 8 + 12 y - 27 z + 6$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = 2 y + 8 + 12 y - 27 z + 6$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = 2 y + 8 + 12 y - 27 z + 6$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Simplify by adding terms.

Add $2 y$ and $12 y$ .

$z = 14 y + 8 - 27 z + 6$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Add $8$ and $6$ .

$z = 14 y - 27 z + 14$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = 14 y - 27 z + 14$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = 14 y - 27 z + 14$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = 14 y - 27 z + 14$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = 14 y - 27 z + 14$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Step 3

Solve for $z$ in $z = 14 y - 27 z + 14$ .

Move all terms containing $z$ to the left side of the equation.

Add $27 z$ to both sides of the equation.

$z + 27 z = 14 y + 14$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Add $z$ and $27 z$ .

$28 z = 14 y + 14$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$28 z = 14 y + 14$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Divide each term in $28 z = 14 y + 14$ by $28$ and simplify.

Divide each term in $28 z = 14 y + 14$ by $28$ .

$\frac{28 z}{28} = \frac{14 y}{28} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Simplify the left side.

Cancel the common factor of $28$ .

Cancel the common factor.

$\frac{28 z}{28} = \frac{14 y}{28} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Divide $z$ by $1$ .

$z = \frac{14 y}{28} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = \frac{14 y}{28} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = \frac{14 y}{28} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Simplify the right side.

Simplify each term.

Cancel the common factor of $14$ and $28$ .

Factor $14$ out of $14 y$ .

$z = \frac{14 (y)}{28} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Cancel the common factors.

Factor $14$ out of $28$ .

$z = \frac{14 y}{14 \cdot 2} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Cancel the common factor.

$z = \frac{14 y}{14 \cdot 2} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Rewrite the expression.

$z = \frac{y}{2} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = \frac{y}{2} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = \frac{y}{2} + \frac{14}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Cancel the common factor of $14$ and $28$ .

Factor $14$ out of $14$ .

$z = \frac{y}{2} + \frac{14 (1)}{28}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Cancel the common factors.

Factor $14$ out of $28$ .

$z = \frac{y}{2} + \frac{14 \cdot 1}{14 \cdot 2}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Cancel the common factor.

$z = \frac{y}{2} + \frac{14 \cdot 1}{14 \cdot 2}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Rewrite the expression.

$z = \frac{y}{2} + \frac{1}{2}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = \frac{y}{2} + \frac{1}{2}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = \frac{y}{2} + \frac{1}{2}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = \frac{y}{2} + \frac{1}{2}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = \frac{y}{2} + \frac{1}{2}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = \frac{y}{2} + \frac{1}{2}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

$z = \frac{y}{2} + \frac{1}{2}$

$y = - 8 y + 22 z - 17$

$x = 4 y - 9 z + 2$

Step 4

Replace all occurrences of $z$ with $\frac{y}{2} + \frac{1}{2}$ in each equation.

Replace all occurrences of $z$ in $y = - 8 y + 22 z - 17$ with $\frac{y}{2} + \frac{1}{2}$ .

$y = - 8 y + 22 (\frac{y}{2} + \frac{1}{2}) - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

Simplify the right side.

Simplify $- 8 y + 22 (\frac{y}{2} + \frac{1}{2}) - 17$ .

Simplify each term.

Apply the distributive property.

$y = - 8 y + 22 (\frac{y}{2}) + 22 (\frac{1}{2}) - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

Cancel the common factor of $2$ .

Factor $2$ out of $22$ .

$y = - 8 y + 2 (11) (\frac{y}{2}) + 22 (\frac{1}{2}) - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

Cancel the common factor.

$y = - 8 y + 2 \cdot (11 (\frac{y}{2})) + 22 (\frac{1}{2}) - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

Rewrite the expression.

$y = - 8 y + 11 y + 22 (\frac{1}{2}) - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

$y = - 8 y + 11 y + 22 (\frac{1}{2}) - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

Cancel the common factor of $2$ .

Factor $2$ out of $22$ .

$y = - 8 y + 11 y + 2 (11) (\frac{1}{2}) - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

Cancel the common factor.

$y = - 8 y + 11 y + 2 \cdot (11 (\frac{1}{2})) - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

Rewrite the expression.

$y = - 8 y + 11 y + 11 - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

$y = - 8 y + 11 y + 11 - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

$y = - 8 y + 11 y + 11 - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

Simplify by adding terms.

Add $- 8 y$ and $11 y$ .

$y = 3 y + 11 - 17$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

Subtract $17$ from $11$ .

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - 9 z + 2$

Replace all occurrences of $z$ in $x = 4 y - 9 z + 2$ with $\frac{y}{2} + \frac{1}{2}$ .

$x = 4 y - 9 (\frac{y}{2} + \frac{1}{2}) + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Simplify the right side.

Simplify $4 y - 9 (\frac{y}{2} + \frac{1}{2}) + 2$ .

Simplify each term.

Apply the distributive property.

$x = 4 y - 9 \frac{y}{2} - 9 (\frac{1}{2}) + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Combine $- 9$ and $\frac{y}{2}$ .

$x = 4 y + \frac{- 9 y}{2} - 9 (\frac{1}{2}) + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Combine $- 9$ and $\frac{1}{2}$ .

$x = 4 y + \frac{- 9 y}{2} + \frac{- 9}{2} + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Simplify each term.

Move the negative in front of the fraction.

$x = 4 y - \frac{(9) y}{2} + \frac{- 9}{2} + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Move the negative in front of the fraction.

$x = 4 y - \frac{9 y}{2} - \frac{9}{2} + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - \frac{9 y}{2} - \frac{9}{2} + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = 4 y - \frac{9 y}{2} - \frac{9}{2} + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

To write $4 y$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x = 4 y \cdot \frac{2}{2} - \frac{9 y}{2} - \frac{9}{2} + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Combine $4 y$ and $\frac{2}{2}$ .

$x = \frac{4 y \cdot 2}{2} - \frac{9 y}{2} - \frac{9}{2} + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Combine the numerators over the common denominator.

$x = \frac{4 y \cdot 2 - 9 y}{2} - \frac{9}{2} + 2$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Combine the numerators over the common denominator.

$x = 2 + \frac{4 y \cdot 2 - 9 y - 9}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Multiply $2$ by $4$ .

$x = 2 + \frac{8 y - 9 y - 9}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Subtract $9 y$ from $8 y$ .

$x = 2 + \frac{- y - 9}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

To write $2$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x = 2 \cdot \frac{2}{2} + \frac{- y - 9}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Simplify terms.

Combine $2$ and $\frac{2}{2}$ .

$x = \frac{2 \cdot 2}{2} + \frac{- y - 9}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Combine the numerators over the common denominator.

$x = \frac{2 \cdot 2 - y - 9}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = \frac{2 \cdot 2 - y - 9}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Simplify the numerator.

Multiply $2$ by $2$ .

$x = \frac{4 - y - 9}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Subtract $9$ from $4$ .

$x = \frac{- y - 5}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = \frac{- y - 5}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Simplify with factoring out.

Factor $- 1$ out of $- y$ .

$x = \frac{- (y) - 5}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Rewrite $- 5$ as $- 1 (5)$ .

$x = \frac{- (y) - 1 \cdot 5}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Factor $- 1$ out of $- (y) - 1 (5)$ .

$x = \frac{- (y + 5)}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Simplify the expression.

Rewrite $- (y + 5)$ as $- 1 (y + 5)$ .

$x = \frac{- 1 (y + 5)}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Move the negative in front of the fraction.

$x = - \frac{y + 5}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = - \frac{y + 5}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = - \frac{y + 5}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = - \frac{y + 5}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = - \frac{y + 5}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

$x = - \frac{y + 5}{2}$

$y = 3 y - 6$

$z = \frac{y}{2} + \frac{1}{2}$

Step 5

Solve for $y$ in $y = 3 y - 6$ .

Move all terms containing $y$ to the left side of the equation.

Subtract $3 y$ from both sides of the equation.

$y - 3 y = - 6$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

Subtract $3 y$ from $y$ .

$- 2 y = - 6$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

$- 2 y = - 6$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

Divide each term in $- 2 y = - 6$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 6$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 6}{- 2}$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 6}{- 2}$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

Divide $y$ by $1$ .

$y = \frac{- 6}{- 2}$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

$y = \frac{- 6}{- 2}$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

$y = \frac{- 6}{- 2}$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

Simplify the right side.

Divide $- 6$ by $- 2$ .

$y = 3$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

$y = 3$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

$y = 3$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

$y = 3$

$x = - \frac{y + 5}{2}$

$z = \frac{y}{2} + \frac{1}{2}$

Step 6

Replace all occurrences of $y$ with $3$ in each equation.

Replace all occurrences of $y$ in $x = - \frac{y + 5}{2}$ with $3$ .

$x = - \frac{(3) + 5}{2}$

$y = 3$

$z = \frac{y}{2} + \frac{1}{2}$

Simplify the right side.

Simplify $- \frac{(3) + 5}{2}$ .

Add $3$ and $5$ .

$x = - \frac{8}{2}$

$y = 3$

$z = \frac{y}{2} + \frac{1}{2}$

Divide $8$ by $2$ .

$x = - 1 \cdot 4$

$y = 3$

$z = \frac{y}{2} + \frac{1}{2}$

Multiply $- 1$ by $4$ .

$x = - 4$

$y = 3$

$z = \frac{y}{2} + \frac{1}{2}$

$x = - 4$

$y = 3$

$z = \frac{y}{2} + \frac{1}{2}$

$x = - 4$

$y = 3$

$z = \frac{y}{2} + \frac{1}{2}$

Replace all occurrences of $y$ in $z = \frac{y}{2} + \frac{1}{2}$ with $3$ .

$z = \frac{3}{2} + \frac{1}{2}$

$x = - 4$

$y = 3$

Simplify the right side.

Simplify $\frac{3}{2} + \frac{1}{2}$ .

Combine the numerators over the common denominator.

$z = \frac{3 + 1}{2}$

$x = - 4$

$y = 3$

Simplify the expression.

Add $3$ and $1$ .

$z = \frac{4}{2}$

$x = - 4$

$y = 3$

Divide $4$ by $2$ .

$z = 2$

$x = - 4$

$y = 3$

$z = 2$

$x = - 4$

$y = 3$

$z = 2$

$x = - 4$

$y = 3$

$z = 2$

$x = - 4$

$y = 3$

$z = 2$

$x = - 4$

$y = 3$

Step 7

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 4, 3, 2)$

Step 8

The result can be shown in multiple forms.

Point Form:

$(- 4, 3, 2)$

Equation Form:

$x = - 4, y = 3, z = 2$

Solve the System of Equations x=2(1+2y)-9z y=2(2z-x)-13 z=2(y+4)+3x

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