Solve the System of Equations x-2y=-19 -5x-2y=-1 6x+0=-18

$x - 2 y = - 19$ $- 5 x - 2 y = - 1$ $6 x + 0 = - 18$

Step 1

Divide each term in $6 x = - 18$ by $6$ and simplify.

Divide each term in $6 x = - 18$ by $6$ .

$\frac{6 x}{6} = \frac{- 18}{6}$

$x - 2 y = - 19$

$- 5 x - 2 y = - 1$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{- 18}{6}$

$x - 2 y = - 19$

$- 5 x - 2 y = - 1$

Divide $x$ by $1$ .

$x = \frac{- 18}{6}$

$x - 2 y = - 19$

$- 5 x - 2 y = - 1$

$x = \frac{- 18}{6}$

$x - 2 y = - 19$

$- 5 x - 2 y = - 1$

$x = \frac{- 18}{6}$

$x - 2 y = - 19$

$- 5 x - 2 y = - 1$

Simplify the right side.

Divide $- 18$ by $6$ .

$x = - 3$

$x - 2 y = - 19$

$- 5 x - 2 y = - 1$

$x = - 3$

$x - 2 y = - 19$

$- 5 x - 2 y = - 1$

$x = - 3$

$x - 2 y = - 19$

$- 5 x - 2 y = - 1$

Step 2

Replace all occurrences of $x$ with $- 3$ in each equation.

Replace all occurrences of $x$ in $x - 2 y = - 19$ with $- 3$ .

$(- 3) - 2 y = - 19$

$x = - 3$

$- 5 x - 2 y = - 1$

Simplify the left side.

Remove parentheses.

$- 3 - 2 y = - 19$

$x = - 3$

$- 5 x - 2 y = - 1$

$- 3 - 2 y = - 19$

$x = - 3$

$- 5 x - 2 y = - 1$

Replace all occurrences of $x$ in $- 5 x - 2 y = - 1$ with $- 3$ .

$- 5 \cdot - 3 - 2 y = - 1$

$- 3 - 2 y = - 19$

$x = - 3$

Simplify the left side.

Multiply $- 5$ by $- 3$ .

$15 - 2 y = - 1$

$- 3 - 2 y = - 19$

$x = - 3$

$15 - 2 y = - 1$

$- 3 - 2 y = - 19$

$x = - 3$

$15 - 2 y = - 1$

$- 3 - 2 y = - 19$

$x = - 3$

Step 3

Solve for $y$ in $15 - 2 y = - 1$ .

Move all terms not containing $y$ to the right side of the equation.

Subtract $15$ from both sides of the equation.

$- 2 y = - 1 - 15$

$- 3 - 2 y = - 19$

$x = - 3$

Subtract $15$ from $- 1$ .

$- 2 y = - 16$

$- 3 - 2 y = - 19$

$x = - 3$

$- 2 y = - 16$

$- 3 - 2 y = - 19$

$x = - 3$

Divide each term in $- 2 y = - 16$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 16$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 16}{- 2}$

$- 3 - 2 y = - 19$

$x = - 3$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 16}{- 2}$

$- 3 - 2 y = - 19$

$x = - 3$

Divide $y$ by $1$ .

$y = \frac{- 16}{- 2}$

$- 3 - 2 y = - 19$

$x = - 3$

$y = \frac{- 16}{- 2}$

$- 3 - 2 y = - 19$

$x = - 3$

$y = \frac{- 16}{- 2}$

$- 3 - 2 y = - 19$

$x = - 3$

Simplify the right side.

Divide $- 16$ by $- 2$ .

$y = 8$

$- 3 - 2 y = - 19$

$x = - 3$

$y = 8$

$- 3 - 2 y = - 19$

$x = - 3$

$y = 8$

$- 3 - 2 y = - 19$

$x = - 3$

$y = 8$

$- 3 - 2 y = - 19$

$x = - 3$

Step 4

Replace all occurrences of $y$ with $8$ in each equation.

Replace all occurrences of $y$ in $- 3 - 2 y = - 19$ with $8$ .

$- 3 - 2 \cdot 8 = - 19$

$y = 8$

$x = - 3$

Simplify the left side.

Simplify $- 3 - 2 \cdot 8$ .

Multiply $- 2$ by $8$ .

$- 3 - 16 = - 19$

$y = 8$

$x = - 3$

Subtract $16$ from $- 3$ .

$- 19 = - 19$

$y = 8$

$x = - 3$

$- 19 = - 19$

$y = 8$

$x = - 3$

$- 19 = - 19$

$y = 8$

$x = - 3$

$- 19 = - 19$

$y = 8$

$x = - 3$

Step 5

Remove any equations from the system that are always true.

$y = 8$

$x = - 3$

Step 6

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 3, 8)$

Step 7

The result can be shown in multiple forms.

Point Form:

$(- 3, 8)$

Equation Form:

$x = - 3, y = 8$

Step 8

Solve the System of Equations x-2y=-19 -5x-2y=-1 6x+0=-18

Related Questions

Support LCMGCF.com by disabling your adblocker.