Solve the System of Equations -x-2y=3 x+2y=-3

$- x - 2 y = 3$ $x + 2 y = - 3$

Subtract $2 y$ from both sides of the equation.

$x = - 3 - 2 y$

$- x - 2 y = 3$

Replace all occurrences of $x$ with $- 3 - 2 y$ in each equation.

Replace all occurrences of $x$ in $- x - 2 y = 3$ with $- 3 - 2 y$ .

$- (- 3 - 2 y) - 2 y = 3$

$x = - 3 - 2 y$

Simplify the left side.

Simplify $- (- 3 - 2 y) - 2 y$ .

Simplify each term.

Apply the distributive property.

$3 - (- 2 y) - 2 y = 3$

$x = - 3 - 2 y$

Multiply $- 1$ by $- 3$ .

$3 - (- 2 y) - 2 y = 3$

$x = - 3 - 2 y$

Multiply $- 2$ by $- 1$ .

$3 + 2 y - 2 y = 3$

$x = - 3 - 2 y$

$3 + 2 y - 2 y = 3$

$x = - 3 - 2 y$

Combine the opposite terms in $3 + 2 y - 2 y$ .

Subtract $2 y$ from $2 y$ .

$3 + 0 = 3$

$x = - 3 - 2 y$

Add $3$ and $0$ .

$3 = 3$

$x = - 3 - 2 y$

$3 = 3$

$x = - 3 - 2 y$

$3 = 3$

$x = - 3 - 2 y$

$3 = 3$

$x = - 3 - 2 y$

$3 = 3$

$x = - 3 - 2 y$

Remove any equations from the system that are always true.

$x = - 3 - 2 y$

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