Solve the System of Equations x-2y=-4 y=1/2x+2

$x - 2 y = - 4$ $y = \frac{1}{2} x + 2$

Add $2 y$ to both sides of the equation.

$x = - 4 + 2 y$

$y = \frac{1}{2} x + 2$

Replace all occurrences of $x$ with $- 4 + 2 y$ in each equation.

Replace all occurrences of $x$ in $y = \frac{1}{2} x + 2$ with $- 4 + 2 y$ .

$y = \frac{1}{2} \cdot (- 4 + 2 y) + 2$

$x = - 4 + 2 y$

Simplify the right side.

Simplify $\frac{1}{2} \cdot (- 4 + 2 y) + 2$ .

Simplify each term.

Apply the distributive property.

$y = \frac{1}{2} \cdot - 4 + \frac{1}{2} \cdot (2 y) + 2$

$x = - 4 + 2 y$

Cancel the common factor of $2$ .

Factor $2$ out of $- 4$ .

$y = \frac{1}{2} \cdot (2 (- 2)) + \frac{1}{2} \cdot (2 y) + 2$

$x = - 4 + 2 y$

Cancel the common factor.

$y = \frac{1}{2} \cdot (2 \cdot - 2) + \frac{1}{2} \cdot (2 y) + 2$

$x = - 4 + 2 y$

Rewrite the expression.

$y = - 2 + \frac{1}{2} \cdot (2 y) + 2$

$x = - 4 + 2 y$

$y = - 2 + \frac{1}{2} \cdot (2 y) + 2$

$x = - 4 + 2 y$

Cancel the common factor of $2$ .

Factor $2$ out of $2 y$ .

$y = - 2 + \frac{1}{2} \cdot (2 (y)) + 2$

$x = - 4 + 2 y$

Cancel the common factor.

$y = - 2 + \frac{1}{2} \cdot (2 y) + 2$

$x = - 4 + 2 y$

Rewrite the expression.

$y = - 2 + y + 2$

$x = - 4 + 2 y$

$y = - 2 + y + 2$

$x = - 4 + 2 y$

$y = - 2 + y + 2$

$x = - 4 + 2 y$

Combine the opposite terms in $- 2 + y + 2$ .

Add $- 2$ and $2$ .

$y = y + 0$

$x = - 4 + 2 y$

Add $y$ and $0$ .

$y = y$

$x = - 4 + 2 y$

$y = y$

$x = - 4 + 2 y$

$y = y$

$x = - 4 + 2 y$

$y = y$

$x = - 4 + 2 y$

$y = y$

$x = - 4 + 2 y$

Remove any equations from the system that are always true.

$x = - 4 + 2 y$

Solve the System of Equations x-2y=-4 y=1/2x+2

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