Solve the System of Equations -x-2y=6 y=-1/2x-3

$- x - 2 y = 6$ $y = - \frac{1}{2} x - 3$

Combine $x$ and $\frac{1}{2}$ .

$y = - \frac{x}{2} - 3$

$- x - 2 y = 6$

Replace all occurrences of $y$ with $- \frac{x}{2} - 3$ in each equation.

Replace all occurrences of $y$ in $- x - 2 y = 6$ with $- \frac{x}{2} - 3$ .

$- x - 2 (- \frac{x}{2} - 3) = 6$

$y = - \frac{x}{2} - 3$

Simplify the left side.

Simplify $- x - 2 (- \frac{x}{2} - 3)$ .

Simplify each term.

Apply the distributive property.

$- x - 2 (- \frac{x}{2}) - 2 \cdot - 3 = 6$

$y = - \frac{x}{2} - 3$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{x}{2}$ into the numerator.

$- x - 2 \frac{- x}{2} - 2 \cdot - 3 = 6$

$y = - \frac{x}{2} - 3$

Factor $2$ out of $- 2$ .

$- x + 2 (- 1) (\frac{- x}{2}) - 2 \cdot - 3 = 6$

$y = - \frac{x}{2} - 3$

Cancel the common factor.

$- x + 2 \cdot (- 1 \frac{- x}{2}) - 2 \cdot - 3 = 6$

$y = - \frac{x}{2} - 3$

Rewrite the expression.

$- x - 1 (- x) - 2 \cdot - 3 = 6$

$y = - \frac{x}{2} - 3$

$- x - 1 (- x) - 2 \cdot - 3 = 6$

$y = - \frac{x}{2} - 3$

Multiply $- 1$ by $- 1$ .

$- x + 1 x - 2 \cdot - 3 = 6$

$y = - \frac{x}{2} - 3$

Multiply $x$ by $1$ .

$- x + x - 2 \cdot - 3 = 6$

$y = - \frac{x}{2} - 3$

Multiply $- 2$ by $- 3$ .

$- x + x + 6 = 6$

$y = - \frac{x}{2} - 3$

$- x + x + 6 = 6$

$y = - \frac{x}{2} - 3$

Simplify by adding terms.

Add $- x$ and $x$ .

$0 + 6 = 6$

$y = - \frac{x}{2} - 3$

Add $0$ and $6$ .

$6 = 6$

$y = - \frac{x}{2} - 3$

$6 = 6$

$y = - \frac{x}{2} - 3$

$6 = 6$

$y = - \frac{x}{2} - 3$

$6 = 6$

$y = - \frac{x}{2} - 3$

$6 = 6$

$y = - \frac{x}{2} - 3$

Remove any equations from the system that are always true.

$y = - \frac{x}{2} - 3$

Solve the System of Equations -x-2y=6 y=-1/2x-3

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