Solve the System of Equations x=3-3y x+3y=-6

$x = 3 - 3 y$ $x + 3 y = - 6$

Reorder $3$ and $- 3 y$ .

$x = - 3 y + 3$

$x + 3 y = - 6$

Replace all occurrences of $x$ with $- 3 y + 3$ in each equation.

Replace all occurrences of $x$ in $x + 3 y = - 6$ with $- 3 y + 3$ .

$(- 3 y + 3) + 3 y = - 6$

$x = - 3 y + 3$

Simplify the left side.

Combine the opposite terms in $(- 3 y + 3) + 3 y$ .

Add $- 3 y$ and $3 y$ .

$0 + 3 = - 6$

$x = - 3 y + 3$

Add $0$ and $3$ .

$3 = - 6$

$x = - 3 y + 3$

$3 = - 6$

$x = - 3 y + 3$

$3 = - 6$

$x = - 3 y + 3$

$3 = - 6$

$x = - 3 y + 3$

Since $3 = - 6$ is not true, there is no solution.

No solution

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