Solve the System of Equations x+4y=7 8y=14-2x

$x + 4 y = 7$ $8 y = 14 - 2 x$

Step 1

Subtract $4 y$ from both sides of the equation.

$x = 7 - 4 y$

$8 y = 14 - 2 x$

Step 2

Replace all occurrences of $x$ with $7 - 4 y$ in each equation.

Replace all occurrences of $x$ in $8 y = 14 - 2 x$ with $7 - 4 y$ .

$8 y = 14 - 2 (7 - 4 y)$

$x = 7 - 4 y$

Simplify the right side.

Simplify $14 - 2 (7 - 4 y)$ .

Simplify each term.

Apply the distributive property.

$8 y = 14 - 2 \cdot 7 - 2 (- 4 y)$

$x = 7 - 4 y$

Multiply $- 2$ by $7$ .

$8 y = 14 - 14 - 2 (- 4 y)$

$x = 7 - 4 y$

Multiply $- 4$ by $- 2$ .

$8 y = 14 - 14 + 8 y$

$x = 7 - 4 y$

$8 y = 14 - 14 + 8 y$

$x = 7 - 4 y$

Simplify by subtracting numbers.

Subtract $14$ from $14$ .

$8 y = 0 + 8 y$

$x = 7 - 4 y$

Add $0$ and $8 y$ .

$8 y = 8 y$

$x = 7 - 4 y$

$8 y = 8 y$

$x = 7 - 4 y$

$8 y = 8 y$

$x = 7 - 4 y$

$8 y = 8 y$

$x = 7 - 4 y$

$8 y = 8 y$

$x = 7 - 4 y$

Step 3

Remove any equations from the system that are always true.

$x = 7 - 4 y$

Step 4