Solve the System of Equations -x-4y+8=0 x+4y=8

$- x - 4 y + 8 = 0$ $x + 4 y = 8$

Step 1

Subtract $4 y$ from both sides of the equation.

$x = 8 - 4 y$

$- x - 4 y + 8 = 0$

Step 2

Replace all occurrences of $x$ with $8 - 4 y$ in each equation.

Replace all occurrences of $x$ in $- x - 4 y + 8 = 0$ with $8 - 4 y$ .

$- (8 - 4 y) - 4 y + 8 = 0$

$x = 8 - 4 y$

Simplify the left side.

Simplify $- (8 - 4 y) - 4 y + 8$ .

Simplify each term.

Apply the distributive property.

$- 1 \cdot 8 - (- 4 y) - 4 y + 8 = 0$

$x = 8 - 4 y$

Multiply $- 1$ by $8$ .

$- 8 - (- 4 y) - 4 y + 8 = 0$

$x = 8 - 4 y$

Multiply $- 4$ by $- 1$ .

$- 8 + 4 y - 4 y + 8 = 0$

$x = 8 - 4 y$

$- 8 + 4 y - 4 y + 8 = 0$

$x = 8 - 4 y$

Combine the opposite terms in $- 8 + 4 y - 4 y + 8$ .

Subtract $4 y$ from $4 y$ .

$- 8 + 0 + 8 = 0$

$x = 8 - 4 y$

Add $- 8$ and $0$ .

$- 8 + 8 = 0$

$x = 8 - 4 y$

Add $- 8$ and $8$ .

$0 = 0$

$x = 8 - 4 y$

$0 = 0$

$x = 8 - 4 y$

$0 = 0$

$x = 8 - 4 y$

$0 = 0$

$x = 8 - 4 y$

$0 = 0$

$x = 8 - 4 y$

Step 3

Remove any equations from the system that are always true.

$x = 8 - 4 y$

Step 4

Solve the System of Equations -x-4y+8=0 x+4y=8

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