Solve the System of Equations x=-4y x+5y=2

$x = - 4 y$ $x + 5 y = 2$

Step 1

Replace all occurrences of $x$ with $- 4 y$ in each equation.

Replace all occurrences of $x$ in $x + 5 y = 2$ with $- 4 y$ .

$(- 4 y) + 5 y = 2$

$x = - 4 y$

Simplify the left side.

Add $- 4 y$ and $5 y$ .

$y = 2$

$x = - 4 y$

$y = 2$

$x = - 4 y$

$y = 2$

$x = - 4 y$

Step 2

Replace all occurrences of $y$ with $2$ in each equation.

Replace all occurrences of $y$ in $x = - 4 y$ with $2$ .

$x = - 4 \cdot 2$

$y = 2$

Simplify the right side.

Multiply $- 4$ by $2$ .

$x = - 8$

$y = 2$

$x = - 8$

$y = 2$

$x = - 8$

$y = 2$

Step 3

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 8, 2)$

Step 4

The result can be shown in multiple forms.

Point Form:

$(- 8, 2)$

Equation Form:

$x = - 8, y = 2$

Step 5