Solve the System of Equations x+7y=0 2x-8y=22

$x + 7 y = 0$ $2 x - 8 y = 22$

Subtract $7 y$ from both sides of the equation.

$x = - 7 y$

$2 x - 8 y = 22$

Replace all occurrences of $x$ with $- 7 y$ in each equation.

Replace all occurrences of $x$ in $2 x - 8 y = 22$ with $- 7 y$ .

$2 (- 7 y) - 8 y = 22$

$x = - 7 y$

Simplify the left side.

Simplify $2 (- 7 y) - 8 y$ .

Multiply $- 7$ by $2$ .

$- 14 y - 8 y = 22$

$x = - 7 y$

Subtract $8 y$ from $- 14 y$ .

$- 22 y = 22$

$x = - 7 y$

$- 22 y = 22$

$x = - 7 y$

$- 22 y = 22$

$x = - 7 y$

$- 22 y = 22$

$x = - 7 y$

Divide each term in $- 22 y = 22$ by $- 22$ and simplify.

Divide each term in $- 22 y = 22$ by $- 22$ .

$\frac{- 22 y}{- 22} = \frac{22}{- 22}$

$x = - 7 y$

Simplify the left side.

Cancel the common factor of $- 22$ .

Cancel the common factor.

$\frac{- 22 y}{- 22} = \frac{22}{- 22}$

$x = - 7 y$

Divide $y$ by $1$ .

$y = \frac{22}{- 22}$

$x = - 7 y$

$y = \frac{22}{- 22}$

$x = - 7 y$

$y = \frac{22}{- 22}$

$x = - 7 y$

Simplify the right side.

Divide $22$ by $- 22$ .

$y = - 1$

$x = - 7 y$

$y = - 1$

$x = - 7 y$

$y = - 1$

$x = - 7 y$

Replace all occurrences of $y$ with $- 1$ in each equation.

Replace all occurrences of $y$ in $x = - 7 y$ with $- 1$ .

$x = - 7 \cdot - 1$

$y = - 1$

Simplify the right side.

Multiply $- 7$ by $- 1$ .

$x = 7$

$y = - 1$

$x = 7$

$y = - 1$

$x = 7$

$y = - 1$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(7, - 1)$

The result can be shown in multiple forms.

Point Form:

$(7, - 1)$

Equation Form:

$x = 7, y = - 1$

Solve the System of Equations x+7y=0 2x-8y=22

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