Solve the System of Equations x+y=0 3x+y=-4

$x + y = 0$ $3 x + y = - 4$

Subtract $y$ from both sides of the equation.

$x = - y$

$3 x + y = - 4$

Replace all occurrences of $x$ with $- y$ in each equation.

Replace all occurrences of $x$ in $3 x + y = - 4$ with $- y$ .

$3 (- y) + y = - 4$

$x = - y$

Simplify the left side.

Simplify $3 (- y) + y$ .

Multiply $- 1$ by $3$ .

$- 3 y + y = - 4$

$x = - y$

Add $- 3 y$ and $y$ .

$- 2 y = - 4$

$x = - y$

$- 2 y = - 4$

$x = - y$

$- 2 y = - 4$

$x = - y$

$- 2 y = - 4$

$x = - y$

Divide each term in $- 2 y = - 4$ by $- 2$ and simplify.

Divide each term in $- 2 y = - 4$ by $- 2$ .

$\frac{- 2 y}{- 2} = \frac{- 4}{- 2}$

$x = - y$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 y}{- 2} = \frac{- 4}{- 2}$

$x = - y$

Divide $y$ by $1$ .

$y = \frac{- 4}{- 2}$

$x = - y$

$y = \frac{- 4}{- 2}$

$x = - y$

$y = \frac{- 4}{- 2}$

$x = - y$

Simplify the right side.

Divide $- 4$ by $- 2$ .

$y = 2$

$x = - y$

$y = 2$

$x = - y$

$y = 2$

$x = - y$

Replace all occurrences of $y$ with $2$ in each equation.

Replace all occurrences of $y$ in $x = - y$ with $2$ .

$x = - (2)$

$y = 2$

Simplify the right side.

Multiply $- 1$ by $2$ .

$x = - 2$

$y = 2$

$x = - 2$

$y = 2$

$x = - 2$

$y = 2$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 2, 2)$

The result can be shown in multiple forms.

Point Form:

$(- 2, 2)$

Equation Form:

$x = - 2, y = 2$

Solve the System of Equations x+y=0 3x+y=-4

Related Questions

Support LCMGCF.com by disabling your adblocker.