Solve the System of Equations x-y=-1 2x-y=0

$x - y = - 1$ $2 x - y = 0$

Add $y$ to both sides of the equation.

$x = - 1 + y$

$2 x - y = 0$

Replace all occurrences of $x$ with $- 1 + y$ in each equation.

Replace all occurrences of $x$ in $2 x - y = 0$ with $- 1 + y$ .

$2 (- 1 + y) - y = 0$

$x = - 1 + y$

Simplify the left side.

Simplify $2 (- 1 + y) - y$ .

Simplify each term.

Apply the distributive property.

$2 \cdot - 1 + 2 y - y = 0$

$x = - 1 + y$

Multiply $2$ by $- 1$ .

$- 2 + 2 y - y = 0$

$x = - 1 + y$

$- 2 + 2 y - y = 0$

$x = - 1 + y$

Subtract $y$ from $2 y$ .

$- 2 + y = 0$

$x = - 1 + y$

$- 2 + y = 0$

$x = - 1 + y$

$- 2 + y = 0$

$x = - 1 + y$

$- 2 + y = 0$

$x = - 1 + y$

Add $2$ to both sides of the equation.

$y = 2$

$x = - 1 + y$

Replace all occurrences of $y$ with $2$ in each equation.

Replace all occurrences of $y$ in $x = - 1 + y$ with $2$ .

$x = - 1 + 2$

$y = 2$

Simplify $x = - 1 + 2$ .

Simplify the left side.

Remove parentheses.

$x = - 1 + 2$

$y = 2$

$x = - 1 + 2$

$y = 2$

Simplify the right side.

Add $- 1$ and $2$ .

$x = 1$

$y = 2$

$x = 1$

$y = 2$

$x = 1$

$y = 2$

$x = 1$

$y = 2$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(1, 2)$

The result can be shown in multiple forms.

Point Form:

$(1, 2)$

Equation Form:

$x = 1, y = 2$

Solve the System of Equations x-y=-1 2x-y=0

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