Solve the System of Equations x=y-1 -x+y=-1

$x = y - 1$ $- x + y = - 1$

Step 1

Replace all occurrences of $x$ with $y - 1$ in each equation.

Replace all occurrences of $x$ in $- x + y = - 1$ with $y - 1$ .

$- (y - 1) + y = - 1$

$x = y - 1$

Simplify the left side.

Simplify $- (y - 1) + y$ .

Simplify each term.

Apply the distributive property.

$- y + 1 + y = - 1$

$x = y - 1$

Multiply $- 1$ by $- 1$ .

$- y + 1 + y = - 1$

$x = y - 1$

$- y + 1 + y = - 1$

$x = y - 1$

Combine the opposite terms in $- y + 1 + y$ .

Add $- y$ and $y$ .

$0 + 1 = - 1$

$x = y - 1$

Add $0$ and $1$ .

$1 = - 1$

$x = y - 1$

$1 = - 1$

$x = y - 1$

$1 = - 1$

$x = y - 1$

$1 = - 1$

$x = y - 1$

$1 = - 1$

$x = y - 1$

Step 2

Since $1 = - 1$ is not true, there is no solution.

No solution

Step 3

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