Solve the System of Equations x=y+2 -3x+3y=6

$x = y + 2$ $- 3 x + 3 y = 6$

Step 1

Replace all occurrences of $x$ with $y + 2$ in each equation.

Replace all occurrences of $x$ in $- 3 x + 3 y = 6$ with $y + 2$ .

$- 3 (y + 2) + 3 y = 6$

$x = y + 2$

Simplify the left side.

Simplify $- 3 (y + 2) + 3 y$ .

Simplify each term.

Apply the distributive property.

$- 3 y - 3 \cdot 2 + 3 y = 6$

$x = y + 2$

Multiply $- 3$ by $2$ .

$- 3 y - 6 + 3 y = 6$

$x = y + 2$

$- 3 y - 6 + 3 y = 6$

$x = y + 2$

Combine the opposite terms in $- 3 y - 6 + 3 y$ .

Add $- 3 y$ and $3 y$ .

$0 - 6 = 6$

$x = y + 2$

Subtract $6$ from $0$ .

$- 6 = 6$

$x = y + 2$

$- 6 = 6$

$x = y + 2$

$- 6 = 6$

$x = y + 2$

$- 6 = 6$

$x = y + 2$

$- 6 = 6$

$x = y + 2$

Step 2

Since $- 6 = 6$ is not true, there is no solution.

No solution

Step 3

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