Solve the System of Equations -x+y+3z=-3 x-2y-2z=8 3x-y-4z=6

$- x + y + 3 z = - 3$ $x - 2 y - 2 z = 8$ $3 x - y - 4 z = 6$

Step 1

Move all terms not containing $y$ to the right side of the equation.

Add $x$ to both sides of the equation.

$y + 3 z = - 3 + x$

$x - 2 y - 2 z = 8$

$3 x - y - 4 z = 6$

Subtract $3 z$ from both sides of the equation.

$y = - 3 + x - 3 z$

$x - 2 y - 2 z = 8$

$3 x - y - 4 z = 6$

$y = - 3 + x - 3 z$

$x - 2 y - 2 z = 8$

$3 x - y - 4 z = 6$

Step 2

Replace all occurrences of $y$ with $- 3 + x - 3 z$ in each equation.

Replace all occurrences of $y$ in $x - 2 y - 2 z = 8$ with $- 3 + x - 3 z$ .

$x - 2 (- 3 + x - 3 z) - 2 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

Simplify the left side.

Simplify $x - 2 (- 3 + x - 3 z) - 2 z$ .

Simplify each term.

Apply the distributive property.

$x - 2 \cdot - 3 - 2 x - 2 (- 3 z) - 2 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

Simplify.

Multiply $- 2$ by $- 3$ .

$x + 6 - 2 x - 2 (- 3 z) - 2 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

Multiply $- 3$ by $- 2$ .

$x + 6 - 2 x + 6 z - 2 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

$x + 6 - 2 x + 6 z - 2 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

$x + 6 - 2 x + 6 z - 2 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

Simplify by adding terms.

Subtract $2 x$ from $x$ .

$- x + 6 + 6 z - 2 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

Subtract $2 z$ from $6 z$ .

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$3 x - y - 4 z = 6$

Replace all occurrences of $y$ in $3 x - y - 4 z = 6$ with $- 3 + x - 3 z$ .

$3 x - (- 3 + x - 3 z) - 4 z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Simplify the left side.

Simplify $3 x - (- 3 + x - 3 z) - 4 z$ .

Simplify each term.

Apply the distributive property.

$3 x + 3 - x - (- 3 z) - 4 z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Simplify.

Multiply $- 1$ by $- 3$ .

$3 x + 3 - x - (- 3 z) - 4 z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Multiply $- 3$ by $- 1$ .

$3 x + 3 - x + 3 z - 4 z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$3 x + 3 - x + 3 z - 4 z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$3 x + 3 - x + 3 z - 4 z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Simplify by adding terms.

Subtract $x$ from $3 x$ .

$2 x + 3 + 3 z - 4 z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Subtract $4 z$ from $3 z$ .

$2 x + 3 - z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$2 x + 3 - z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$2 x + 3 - z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$2 x + 3 - z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$2 x + 3 - z = 6$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Step 3

Solve for $x$ in $2 x + 3 - z = 6$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$2 x - z = 6 - 3$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Add $z$ to both sides of the equation.

$2 x = 6 - 3 + z$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Subtract $3$ from $6$ .

$2 x = 3 + z$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$2 x = 3 + z$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Divide each term in $2 x = 3 + z$ by $2$ and simplify.

Divide each term in $2 x = 3 + z$ by $2$ .

$\frac{2 x}{2} = \frac{3}{2} + \frac{z}{2}$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{3}{2} + \frac{z}{2}$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Divide $x$ by $1$ .

$x = \frac{3}{2} + \frac{z}{2}$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$x = \frac{3}{2} + \frac{z}{2}$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$x = \frac{3}{2} + \frac{z}{2}$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$x = \frac{3}{2} + \frac{z}{2}$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

$x = \frac{3}{2} + \frac{z}{2}$

$- x + 6 + 4 z = 8$

$y = - 3 + x - 3 z$

Step 4

Replace all occurrences of $x$ with $\frac{3}{2} + \frac{z}{2}$ in each equation.

Replace all occurrences of $x$ in $- x + 6 + 4 z = 8$ with $\frac{3}{2} + \frac{z}{2}$ .

$- (\frac{3}{2} + \frac{z}{2}) + 6 + 4 z = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Simplify the left side.

Simplify $- (\frac{3}{2} + \frac{z}{2}) + 6 + 4 z$ .

Apply the distributive property.

$- \frac{3}{2} - \frac{z}{2} + 6 + 4 z = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

To write $6$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- \frac{z}{2} - \frac{3}{2} + 6 \cdot \frac{2}{2} + 4 z = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Combine $6$ and $\frac{2}{2}$ .

$- \frac{z}{2} - \frac{3}{2} + \frac{6 \cdot 2}{2} + 4 z = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Combine the numerators over the common denominator.

$- \frac{z}{2} + \frac{- 3 + 6 \cdot 2}{2} + 4 z = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Simplify the numerator.

Multiply $6$ by $2$ .

$- \frac{z}{2} + \frac{- 3 + 12}{2} + 4 z = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Add $- 3$ and $12$ .

$- \frac{z}{2} + \frac{9}{2} + 4 z = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

$- \frac{z}{2} + \frac{9}{2} + 4 z = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

To write $4 z$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- \frac{z}{2} + 4 z \cdot \frac{2}{2} + \frac{9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Combine $4 z$ and $\frac{2}{2}$ .

$- \frac{z}{2} + \frac{4 z \cdot 2}{2} + \frac{9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Combine the numerators over the common denominator.

$\frac{- z + 4 z \cdot 2}{2} + \frac{9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Combine the numerators over the common denominator.

$\frac{- z + 4 z \cdot 2 + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Multiply $2$ by $4$ .

$\frac{- z + 8 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Add $- z$ and $8 z$ .

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + x - 3 z$

Replace all occurrences of $x$ in $y = - 3 + x - 3 z$ with $\frac{3}{2} + \frac{z}{2}$ .

$y = - 3 + \frac{3}{2} + \frac{z}{2} - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Simplify $y = - 3 + \frac{3}{2} + \frac{z}{2} - 3 z$ .

Simplify the left side.

Remove parentheses.

$y = - 3 + \frac{3}{2} + \frac{z}{2} - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 3 + \frac{3}{2} + \frac{z}{2} - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Simplify the right side.

Simplify $- 3 + \frac{3}{2} + \frac{z}{2} - 3 z$ .

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y = - 3 \cdot \frac{2}{2} + \frac{3}{2} + \frac{z}{2} - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Combine $- 3$ and $\frac{2}{2}$ .

$y = \frac{- 3 \cdot 2}{2} + \frac{3}{2} + \frac{z}{2} - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Combine the numerators over the common denominator.

$y = \frac{- 3 \cdot 2 + 3}{2} + \frac{z}{2} - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Simplify the numerator.

Multiply $- 3$ by $2$ .

$y = \frac{- 6 + 3}{2} + \frac{z}{2} - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Add $- 6$ and $3$ .

$y = \frac{- 3}{2} + \frac{z}{2} - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = \frac{- 3}{2} + \frac{z}{2} - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Move the negative in front of the fraction.

$y = - \frac{3}{2} + \frac{z}{2} - 3 z$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

To write $- 3 z$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y = - \frac{3}{2} + \frac{z}{2} - 3 z \cdot \frac{2}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Combine $- 3 z$ and $\frac{2}{2}$ .

$y = - \frac{3}{2} + \frac{z}{2} + \frac{- 3 z \cdot 2}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Combine the numerators over the common denominator.

$y = - \frac{3}{2} + \frac{z - 3 z \cdot 2}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Combine the numerators over the common denominator.

$y = \frac{- 3 + z - 3 z \cdot 2}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Multiply $2$ by $- 3$ .

$y = \frac{- 3 + z - 6 z}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Subtract $6 z$ from $z$ .

$y = \frac{- 3 - 5 z}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Rewrite $- 3$ as $- 1 (3)$ .

$y = \frac{- 1 \cdot 3 - 5 z}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Factor $- 1$ out of $- 5 z$ .

$y = \frac{- 1 \cdot 3 - (5 z)}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Factor $- 1$ out of $- 1 (3) - (5 z)$ .

$y = \frac{- 1 (3 + 5 z)}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Move the negative in front of the fraction.

$y = - \frac{3 + 5 z}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - \frac{3 + 5 z}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - \frac{3 + 5 z}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - \frac{3 + 5 z}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - \frac{3 + 5 z}{2}$

$\frac{7 z + 9}{2} = 8$

$x = \frac{3}{2} + \frac{z}{2}$

Step 5

Solve for $z$ in $\frac{7 z + 9}{2} = 8$ .

Multiply both sides by $2$ .

$\frac{7 z + 9}{2} \cdot 2 = 8 \cdot 2$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

Simplify.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{7 z + 9}{2} \cdot 2 = 8 \cdot 2$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

Rewrite the expression.

$7 z + 9 = 8 \cdot 2$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$7 z + 9 = 8 \cdot 2$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$7 z + 9 = 8 \cdot 2$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

Simplify the right side.

Multiply $8$ by $2$ .

$7 z + 9 = 16$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$7 z + 9 = 16$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$7 z + 9 = 16$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

Solve for $z$ .

Move all terms not containing $z$ to the right side of the equation.

Subtract $9$ from both sides of the equation.

$7 z = 16 - 9$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

Subtract $9$ from $16$ .

$7 z = 7$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$7 z = 7$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

Divide each term in $7 z = 7$ by $7$ and simplify.

Divide each term in $7 z = 7$ by $7$ .

$\frac{7 z}{7} = \frac{7}{7}$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 z}{7} = \frac{7}{7}$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

Divide $z$ by $1$ .

$z = \frac{7}{7}$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$z = \frac{7}{7}$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$z = \frac{7}{7}$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

Simplify the right side.

Divide $7$ by $7$ .

$z = 1$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$z = 1$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$z = 1$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$z = 1$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

$z = 1$

$y = - \frac{3 + 5 z}{2}$

$x = \frac{3}{2} + \frac{z}{2}$

Step 6

Replace all occurrences of $z$ with $1$ in each equation.

Replace all occurrences of $z$ in $y = - \frac{3 + 5 z}{2}$ with $1$ .

$y = - \frac{3 + 5 (1)}{2}$

$z = 1$

$x = \frac{3}{2} + \frac{z}{2}$

Simplify the right side.

Simplify $- \frac{3 + 5 (1)}{2}$ .

Simplify the numerator.

Multiply $5$ by $1$ .

$y = - \frac{3 + 5}{2}$

$z = 1$

$x = \frac{3}{2} + \frac{z}{2}$

Add $3$ and $5$ .

$y = - \frac{8}{2}$

$z = 1$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - \frac{8}{2}$

$z = 1$

$x = \frac{3}{2} + \frac{z}{2}$

Simplify the expression.

Divide $8$ by $2$ .

$y = - 1 \cdot 4$

$z = 1$

$x = \frac{3}{2} + \frac{z}{2}$

Multiply $- 1$ by $4$ .

$y = - 4$

$z = 1$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 4$

$z = 1$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 4$

$z = 1$

$x = \frac{3}{2} + \frac{z}{2}$

$y = - 4$

$z = 1$

$x = \frac{3}{2} + \frac{z}{2}$

Replace all occurrences of $z$ in $x = \frac{3}{2} + \frac{z}{2}$ with $1$ .

$x = \frac{3}{2} + \frac{1}{2}$

$y = - 4$

$z = 1$

Simplify the right side.

Simplify $\frac{3}{2} + \frac{1}{2}$ .

Combine the numerators over the common denominator.

$x = \frac{3 + 1}{2}$

$y = - 4$

$z = 1$

Simplify the expression.

Add $3$ and $1$ .

$x = \frac{4}{2}$

$y = - 4$

$z = 1$

Divide $4$ by $2$ .

$x = 2$

$y = - 4$

$z = 1$

$x = 2$

$y = - 4$

$z = 1$

$x = 2$

$y = - 4$

$z = 1$

$x = 2$

$y = - 4$

$z = 1$

$x = 2$

$y = - 4$

$z = 1$

Step 7

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, - 4, 1)$

Step 8

The result can be shown in multiple forms.

Point Form:

$(2, - 4, 1)$

Equation Form:

$x = 2, y = - 4, z = 1$

Solve the System of Equations -x+y+3z=-3 x-2y-2z=8 3x-y-4z=6

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