Solve the System of Equations y=-1/2x+8 x-4y=-8

$y = - \frac{1}{2} x + 8$ $x - 4 y = - 8$

Combine $x$ and $\frac{1}{2}$ .

$y = - \frac{x}{2} + 8$

$x - 4 y = - 8$

Replace all occurrences of $y$ with $- \frac{x}{2} + 8$ in each equation.

Replace all occurrences of $y$ in $x - 4 y = - 8$ with $- \frac{x}{2} + 8$ .

$x - 4 (- \frac{x}{2} + 8) = - 8$

$y = - \frac{x}{2} + 8$

Simplify the left side.

Simplify $x - 4 (- \frac{x}{2} + 8)$ .

Simplify each term.

Apply the distributive property.

$x - 4 (- \frac{x}{2}) - 4 \cdot 8 = - 8$

$y = - \frac{x}{2} + 8$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{x}{2}$ into the numerator.

$x - 4 \frac{- x}{2} - 4 \cdot 8 = - 8$

$y = - \frac{x}{2} + 8$

Factor $2$ out of $- 4$ .

$x + 2 (- 2) (\frac{- x}{2}) - 4 \cdot 8 = - 8$

$y = - \frac{x}{2} + 8$

Cancel the common factor.

$x + 2 \cdot (- 2 \frac{- x}{2}) - 4 \cdot 8 = - 8$

$y = - \frac{x}{2} + 8$

Rewrite the expression.

$x - 2 (- x) - 4 \cdot 8 = - 8$

$y = - \frac{x}{2} + 8$

$x - 2 (- x) - 4 \cdot 8 = - 8$

$y = - \frac{x}{2} + 8$

Multiply $- 1$ by $- 2$ .

$x + 2 x - 4 \cdot 8 = - 8$

$y = - \frac{x}{2} + 8$

Multiply $- 4$ by $8$ .

$x + 2 x - 32 = - 8$

$y = - \frac{x}{2} + 8$

$x + 2 x - 32 = - 8$

$y = - \frac{x}{2} + 8$

Add $x$ and $2 x$ .

$3 x - 32 = - 8$

$y = - \frac{x}{2} + 8$

$3 x - 32 = - 8$

$y = - \frac{x}{2} + 8$

$3 x - 32 = - 8$

$y = - \frac{x}{2} + 8$

$3 x - 32 = - 8$

$y = - \frac{x}{2} + 8$

Solve for $x$ in $3 x - 32 = - 8$ .

Move all terms not containing $x$ to the right side of the equation.

Add $32$ to both sides of the equation.

$3 x = - 8 + 32$

$y = - \frac{x}{2} + 8$

Add $- 8$ and $32$ .

$3 x = 24$

$y = - \frac{x}{2} + 8$

$3 x = 24$

$y = - \frac{x}{2} + 8$

Divide each term in $3 x = 24$ by $3$ and simplify.

Divide each term in $3 x = 24$ by $3$ .

$\frac{3 x}{3} = \frac{24}{3}$

$y = - \frac{x}{2} + 8$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{24}{3}$

$y = - \frac{x}{2} + 8$

Divide $x$ by $1$ .

$x = \frac{24}{3}$

$y = - \frac{x}{2} + 8$

$x = \frac{24}{3}$

$y = - \frac{x}{2} + 8$

$x = \frac{24}{3}$

$y = - \frac{x}{2} + 8$

Simplify the right side.

Divide $24$ by $3$ .

$x = 8$

$y = - \frac{x}{2} + 8$

$x = 8$

$y = - \frac{x}{2} + 8$

$x = 8$

$y = - \frac{x}{2} + 8$

$x = 8$

$y = - \frac{x}{2} + 8$

Replace all occurrences of $x$ with $8$ in each equation.

Replace all occurrences of $x$ in $y = - \frac{x}{2} + 8$ with $8$ .

$y = - \frac{8}{2} + 8$

$x = 8$

Simplify the right side.

Simplify $- \frac{8}{2} + 8$ .

Simplify each term.

Divide $8$ by $2$ .

$y = - 1 \cdot 4 + 8$

$x = 8$

Multiply $- 1$ by $4$ .

$y = - 4 + 8$

$x = 8$

$y = - 4 + 8$

$x = 8$

Add $- 4$ and $8$ .

$y = 4$

$x = 8$

$y = 4$

$x = 8$

$y = 4$

$x = 8$

$y = 4$

$x = 8$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(8, 4)$

The result can be shown in multiple forms.

Point Form:

$(8, 4)$

Equation Form:

$x = 8, y = 4$

Solve the System of Equations y=-1/2x+8 x-4y=-8

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