Solve the System of Equations y=-1 3x+y=16

$y = - 1$ $3 x + y = 16$

Step 1

Replace all occurrences of $y$ with $- 1$ in each equation.

Replace all occurrences of $y$ in $3 x + y = 16$ with $- 1$ .

$3 x - 1 = 16$

$y = - 1$

Simplify the left side.

Remove parentheses.

$3 x - 1 = 16$

$y = - 1$

$3 x - 1 = 16$

$y = - 1$

$3 x - 1 = 16$

$y = - 1$

Step 2

Solve for $x$ in $3 x - 1 = 16$ .

Move all terms not containing $x$ to the right side of the equation.

Add $1$ to both sides of the equation.

$3 x = 16 + 1$

$y = - 1$

Add $16$ and $1$ .

$3 x = 17$

$y = - 1$

$3 x = 17$

$y = - 1$

Divide each term in $3 x = 17$ by $3$ and simplify.

Divide each term in $3 x = 17$ by $3$ .

$\frac{3 x}{3} = \frac{17}{3}$

$y = - 1$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{17}{3}$

$y = - 1$

Divide $x$ by $1$ .

$x = \frac{17}{3}$

$y = - 1$

$x = \frac{17}{3}$

$y = - 1$

$x = \frac{17}{3}$

$y = - 1$

$x = \frac{17}{3}$

$y = - 1$

$x = \frac{17}{3}$

$y = - 1$

Step 3

Solve the system of equations $x = \frac{17}{3} y = - 1$ .

$x = \frac{17}{3} y = - 1$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(\frac{17}{3}, - 1)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(\frac{17}{3}, - 1)$

Equation Form:

$x = \frac{17}{3}, y = - 1$

Step 6

Solve the System of Equations y=-1 3x+y=16

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