Solve the System of Equations y=2x-3 y-2x=-3

$y = 2 x - 3$ $y - 2 x = - 3$

Step 1

Replace all occurrences of $y$ with $2 x - 3$ in each equation.

Replace all occurrences of $y$ in $y - 2 x = - 3$ with $2 x - 3$ .

$(2 x - 3) - 2 x = - 3$

$y = 2 x - 3$

Simplify the left side.

Combine the opposite terms in $(2 x - 3) - 2 x$ .

Subtract $2 x$ from $2 x$ .

$0 - 3 = - 3$

$y = 2 x - 3$

Subtract $3$ from $0$ .

$- 3 = - 3$

$y = 2 x - 3$

$- 3 = - 3$

$y = 2 x - 3$

$- 3 = - 3$

$y = 2 x - 3$

$- 3 = - 3$

$y = 2 x - 3$

Step 2

Remove any equations from the system that are always true.

$y = 2 x - 3$

Step 3

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