Solve the System of Equations y=-2x-4 y=x+2

$y = - 2 x - 4$ $y = x + 2$

Eliminate the equal sides of each equation and combine.

$- 2 x - 4 = x + 2$

Solve $- 2 x - 4 = x + 2$ for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$- 2 x - 4 - x = 2$

Subtract $x$ from $- 2 x$ .

$- 3 x - 4 = 2$

Move all terms not containing $x$ to the right side of the equation.

Add $4$ to both sides of the equation.

$- 3 x = 2 + 4$

Add $2$ and $4$ .

$- 3 x = 6$

Divide each term in $- 3 x = 6$ by $- 3$ and simplify.

Divide each term in $- 3 x = 6$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{6}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{6}{- 3}$

Divide $x$ by $1$ .

$x = \frac{6}{- 3}$

Simplify the right side.

Divide $6$ by $- 3$ .

$x = - 2$

Evaluate $y$ when $x = - 2$ .

Substitute $- 2$ for $x$ .

$y = (- 2) + 2$

Substitute $- 2$ for $x$ in $y = (- 2) + 2$ and solve for $y$ .

Remove parentheses.

$y = - 2 + 2$

Remove parentheses.

$y = (- 2) + 2$

Add $- 2$ and $2$ .

$y = 0$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 2, 0)$

The result can be shown in multiple forms.

Point Form:

$(- 2, 0)$

Equation Form:

$x = - 2, y = 0$