Solve the System of Equations y=-3/2x-8 3x-4y=-4

$y = - \frac{3}{2} x - 8$ $3 x - 4 y = - 4$

Simplify each term.

Combine $x$ and $\frac{3}{2}$ .

$y = - \frac{x \cdot 3}{2} - 8$

$3 x - 4 y = - 4$

Move $3$ to the left of $x$ .

$y = - \frac{3 x}{2} - 8$

$3 x - 4 y = - 4$

$y = - \frac{3 x}{2} - 8$

$3 x - 4 y = - 4$

Replace all occurrences of $y$ with $- \frac{3 x}{2} - 8$ in each equation.

Replace all occurrences of $y$ in $3 x - 4 y = - 4$ with $- \frac{3 x}{2} - 8$ .

$3 x - 4 (- \frac{3 x}{2} - 8) = - 4$

$y = - \frac{3 x}{2} - 8$

Simplify the left side.

Simplify $3 x - 4 (- \frac{3 x}{2} - 8)$ .

Simplify each term.

Apply the distributive property.

$3 x - 4 (- \frac{3 x}{2}) - 4 \cdot - 8 = - 4$

$y = - \frac{3 x}{2} - 8$

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{3 x}{2}$ into the numerator.

$3 x - 4 \frac{- 3 x}{2} - 4 \cdot - 8 = - 4$

$y = - \frac{3 x}{2} - 8$

Factor $2$ out of $- 4$ .

$3 x + 2 (- 2) (\frac{- 3 x}{2}) - 4 \cdot - 8 = - 4$

$y = - \frac{3 x}{2} - 8$

Cancel the common factor.

$3 x + 2 \cdot (- 2 \frac{- 3 x}{2}) - 4 \cdot - 8 = - 4$

$y = - \frac{3 x}{2} - 8$

Rewrite the expression.

$3 x - 2 (- 3 x) - 4 \cdot - 8 = - 4$

$y = - \frac{3 x}{2} - 8$

$3 x - 2 (- 3 x) - 4 \cdot - 8 = - 4$

$y = - \frac{3 x}{2} - 8$

Multiply $- 3$ by $- 2$ .

$3 x + 6 x - 4 \cdot - 8 = - 4$

$y = - \frac{3 x}{2} - 8$

Multiply $- 4$ by $- 8$ .

$3 x + 6 x + 32 = - 4$

$y = - \frac{3 x}{2} - 8$

$3 x + 6 x + 32 = - 4$

$y = - \frac{3 x}{2} - 8$

Add $3 x$ and $6 x$ .

$9 x + 32 = - 4$

$y = - \frac{3 x}{2} - 8$

$9 x + 32 = - 4$

$y = - \frac{3 x}{2} - 8$

$9 x + 32 = - 4$

$y = - \frac{3 x}{2} - 8$

$9 x + 32 = - 4$

$y = - \frac{3 x}{2} - 8$

Solve for $x$ in $9 x + 32 = - 4$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $32$ from both sides of the equation.

$9 x = - 4 - 32$

$y = - \frac{3 x}{2} - 8$

Subtract $32$ from $- 4$ .

$9 x = - 36$

$y = - \frac{3 x}{2} - 8$

$9 x = - 36$

$y = - \frac{3 x}{2} - 8$

Divide each term in $9 x = - 36$ by $9$ and simplify.

Divide each term in $9 x = - 36$ by $9$ .

$\frac{9 x}{9} = \frac{- 36}{9}$

$y = - \frac{3 x}{2} - 8$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} = \frac{- 36}{9}$

$y = - \frac{3 x}{2} - 8$

Divide $x$ by $1$ .

$x = \frac{- 36}{9}$

$y = - \frac{3 x}{2} - 8$

$x = \frac{- 36}{9}$

$y = - \frac{3 x}{2} - 8$

$x = \frac{- 36}{9}$

$y = - \frac{3 x}{2} - 8$

Simplify the right side.

Divide $- 36$ by $9$ .

$x = - 4$

$y = - \frac{3 x}{2} - 8$

$x = - 4$

$y = - \frac{3 x}{2} - 8$

$x = - 4$

$y = - \frac{3 x}{2} - 8$

$x = - 4$

$y = - \frac{3 x}{2} - 8$

Replace all occurrences of $x$ with $- 4$ in each equation.

Replace all occurrences of $x$ in $y = - \frac{3 x}{2} - 8$ with $- 4$ .

$y = - \frac{3 (- 4)}{2} - 8$

$x = - 4$

Simplify the right side.

Simplify $- \frac{3 (- 4)}{2} - 8$ .

Simplify each term.

Cancel the common factor of $- 4$ and $2$ .

Factor $2$ out of $3 (- 4)$ .

$y = - \frac{2 (3 \cdot (- 2))}{2} - 8$

$x = - 4$

Cancel the common factors.

Factor $2$ out of $2$ .

$y = - \frac{2 (3 \cdot (- 2))}{2 (1)} - 8$

$x = - 4$

Cancel the common factor.

$y = - \frac{2 (3 \cdot (- 2))}{2 \cdot 1} - 8$

$x = - 4$

Rewrite the expression.

$y = - \frac{3 \cdot (- 2)}{1} - 8$

$x = - 4$

Divide $3 \cdot (- 2)$ by $1$ .

$y = - (3 \cdot (- 2)) - 8$

$x = - 4$

$y = - (3 \cdot (- 2)) - 8$

$x = - 4$

$y = - (3 \cdot (- 2)) - 8$

$x = - 4$

Multiply $3$ by $- 2$ .

$y = 6 - 8$

$x = - 4$

Multiply $- 1$ by $- 6$ .

$y = 6 - 8$

$x = - 4$

$y = 6 - 8$

$x = - 4$

Subtract $8$ from $6$ .

$y = - 2$

$x = - 4$

$y = - 2$

$x = - 4$

$y = - 2$

$x = - 4$

$y = - 2$

$x = - 4$

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 4, - 2)$

The result can be shown in multiple forms.

Point Form:

$(- 4, - 2)$

Equation Form:

$x = - 4, y = - 2$

Solve the System of Equations y=-3/2x-8 3x-4y=-4

Related Questions

Support LCMGCF.com by disabling your adblocker.