Solve the System of Equations y+4x=3 y=-4x-1

$y + 4 x = 3$ $y = - 4 x - 1$

Step 1

Replace all occurrences of $y$ with $- 4 x - 1$ in each equation.

Replace all occurrences of $y$ in $y + 4 x = 3$ with $- 4 x - 1$ .

$(- 4 x - 1) + 4 x = 3$

$y = - 4 x - 1$

Simplify the left side.

Combine the opposite terms in $(- 4 x - 1) + 4 x$ .

Add $- 4 x$ and $4 x$ .

$0 - 1 = 3$

$y = - 4 x - 1$

Subtract $1$ from $0$ .

$- 1 = 3$

$y = - 4 x - 1$

$- 1 = 3$

$y = - 4 x - 1$

$- 1 = 3$

$y = - 4 x - 1$

$- 1 = 3$

$y = - 4 x - 1$

Step 2

Since $- 1 = 3$ is not true, there is no solution.

No solution

Step 3

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