Solve the System of Equations y=x+4 2x-2y=10

$y = x + 4$ $2 x - 2 y = 10$

Replace all occurrences of $y$ with $x + 4$ in each equation.

Replace all occurrences of $y$ in $2 x - 2 y = 10$ with $x + 4$ .

$2 x - 2 (x + 4) = 10$

$y = x + 4$

Simplify the left side.

Simplify $2 x - 2 (x + 4)$ .

Simplify each term.

Apply the distributive property.

$2 x - 2 x - 2 \cdot 4 = 10$

$y = x + 4$

Multiply $- 2$ by $4$ .

$2 x - 2 x - 8 = 10$

$y = x + 4$

$2 x - 2 x - 8 = 10$

$y = x + 4$

Simplify by adding terms.

Subtract $2 x$ from $2 x$ .

$0 - 8 = 10$

$y = x + 4$

Subtract $8$ from $0$ .

$- 8 = 10$

$y = x + 4$

$- 8 = 10$

$y = x + 4$

$- 8 = 10$

$y = x + 4$

$- 8 = 10$

$y = x + 4$

$- 8 = 10$

$y = x + 4$

Since $- 8 = 10$ is not true, there is no solution.

No solution

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