Solve the System of Inequalities 10<x+2 or x+2<14

$10 < x + 2$ or $x + 2 < 14$

Simplify the first inequality.

Rewrite so $x$ is on the left side of the inequality.

$x + 2 > 10$ or $x + 2 < 14$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $2$ from both sides of the inequality.

$x > 10 - 2$ or $x + 2 < 14$

Subtract $2$ from $10$ .

$x > 8$ or $x + 2 < 14$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $2$ from both sides of the inequality.

$x > 8$ or $x < 14 - 2$

Subtract $2$ from $14$ .

$x > 8$ or $x < 12$

The union consists of all of the elements that are contained in each interval.

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$