Solve the System of Inequalities 20<=-5x+10 or -35>-5x+10

Subtract ${\displaystyle 10}$ from both sides of the inequality.

${\displaystyle -5x\ge 20-10}$ or ${\displaystyle -35>-5x+10}$

Subtract ${\displaystyle 10}$ from ${\displaystyle 20}$.

${\displaystyle -5x\ge 10}$ or ${\displaystyle -35>-5x+10}$

Divide each term in ${\displaystyle -5x\ge 10}$ by ${\displaystyle -5}$. When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

${\displaystyle \frac{-5x}{-5}\le \frac{10}{-5}}$ or ${\displaystyle -35>-5x+10}$

Simplify the left side.

${\displaystyle x\le \frac{10}{-5}}$ or ${\displaystyle -35>-5x+10}$

Simplify the right side.

${\displaystyle x\le -2}$ or ${\displaystyle -35>-5x+10}$

Subtract ${\displaystyle 10}$ from both sides of the inequality.

${\displaystyle x\le -2}$ or ${\displaystyle -5x<-35-10}$

Subtract ${\displaystyle 10}$ from ${\displaystyle -35}$.

${\displaystyle x\le -2}$ or ${\displaystyle -5x<-45}$

Divide each term in ${\displaystyle -5x<-45}$ by ${\displaystyle -5}$. When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

${\displaystyle x\le -2}$ or ${\displaystyle \frac{-5x}{-5}>\frac{-45}{-5}}$

Simplify the left side.

${\displaystyle x\le -2}$ or ${\displaystyle x>\frac{-45}{-5}}$

Simplify the right side.

${\displaystyle x\le -2}$ or ${\displaystyle x>9}$