Solve the System of Inequalities 24>-3r>-9

$24 > - 3 r > - 9$

Solve $24 > - 3 r$ for $r$ .

Rewrite so $r$ is on the left side of the inequality.

$- 3 r < 24$

Divide each term in $- 3 r < 24$ by $- 3$ and simplify.

Divide each term in $- 3 r < 24$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 r}{- 3} > \frac{24}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 r}{- 3} > \frac{24}{- 3}$

Divide $r$ by $1$ .

$r > \frac{24}{- 3}$

Simplify the right side.

Divide $24$ by $- 3$ .

$r > - 8$

Divide each term in $- 3 r > - 9$ by $- 3$ and simplify.

Divide each term in $- 3 r > - 9$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 r}{- 3} < \frac{- 9}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 r}{- 3} < \frac{- 9}{- 3}$

Divide $r$ by $1$ .

$r < \frac{- 9}{- 3}$

Simplify the right side.

Divide $- 9$ by $- 3$ .

$r < 3$

Find the intersection of $r > - 8$ and $r < 3$ .

$- 8 < r < 3$

The result can be shown in multiple forms.

Inequality Form:

$- 8 < r < 3$

Interval Notation:

$(- 8, 3)$

Solve the System of Inequalities 24>-3r>-9

Related Questions

Support LCMGCF.com by disabling your adblocker.